如何使用 Powershell 通过查找每个文件夹名称中包含的匹配字符串将一个文件夹复制到另一个文件夹

Question

我是新手，所以希望我做对了。在过去的几天里，我做了相当多的研究，我一直在努力处理这段代码，但我无法让它做我想做的事。

我有一个包含多个目录的源目录。我有一个包含多个目录的目标目录。目录的名称中都有一个四位数字，但不在名称的同一位置。我想在每个源目录的名称中找到该编号，并使用该编号在目标目录中查找名称中具有相同编号的目录。找到匹配的目标目录后，将文件夹名称为 33-fit-1234 的源目录移动到具有匹配编号的目标目录中，即。 33-F-1234。我目前正在通过复制然后删除源来进行移动。

源文件夹名称可以是 33-ait-1743A 或 33-xx-4533 UNKNOWN 等
目标文件夹名称的格式均为：33-x-####，其中一些具有单个字母后缀，例如 A、B 等

代码如下：

$sourceDirectory = "D:\Test Source"
$destinationDirectory = "D:\Test Dest"

$sourceFolders = Get-ChildItem -Path $sourceDirectory -Directory | Select-Object -ExpandProperty Name
$destinationFolders = Get-ChildItem -Path $destinationDirectory -Directory | Select-Object -ExpandProperty Name
$matchesInBoth = $sourceFolders -match "\d{4}" | ?{$_ -eq $_}
$matchesInBoth | ForEach-Object{
    $sourcePath = (Join-Path $sourceDirectory $_)
    Copy-Item -Path $sourcePath -Destination 
$destinationDirectory$matchesInBoth$_ -Recurse -whatif
    Remove-Item $sourcePath -Force -Recurse -WhatIf 
}

很接近，我得到的输出是：

What if: Performing the operation "Copy Directory" on target "Item: D:\Test 
Source-FV-1414 Destination: D:\Test Dest-FIT-1414 33-FIT-1576 33-FIT- 
1654A 33-fred-1234 unknown 33-FSL-1649 33-FV-1414 33-FV-1654 33-FV-1882 
33-H-1657 33-H-1814 33-H-1924-FV-1414".
What if: Performing the operation "Remove Directory" on target "D:\Test 
Source-FV-1414".

问题是：我最终将源文件夹复制到一个以我的源目录中所有文件夹名称命名的新文件夹中。

我也试过这段代码没有结果：

$sourceDirectory = "D:\Test Source"
$destinationDirectory = "D:\Test Dest"

$sourceFolders = Get-ChildItem -Path $sourceDirectory -Directory | Select-    Object -ExpandProperty BaseName | Select-String "\d{4}"
$destinationFolders = Get-ChildItem -Path $destinationDirectory -Directory | Select-Object -ExpandProperty BaseName

$matchesInBoth = $destinationFolders | ?{$_ -contains $sourceFolders}
$matchesInBoth | ForEach-Object{
$sourcePath = (Join-Path $sourceDirectory $_)
Copy-Item -Path $sourcePath -Destination $destinationDirectory$matchesInBoth$_ -Recurse -whatif
Remove-Item $sourcePath -Force -Recurse -WhatIf 
}

源文件夹名称是：

"D:\Test Source-FIT-1414"
"D:\Test Source-FIT-1576"
"D:\Test Source-FIT-1654A"
"D:\Test Source-fred-1234 unknown"
"D:\Test Source-FSL-1649"
"D:\Test Source-FV-1414"
"D:\Test Source-FV-1654"
"D:\Test Source-FV-1882"
"D:\Test Source-H-1657"
"D:\Test Source-H-1814"
"D:\Test Source-H-1924"
"D:\Test Source\asjhdsdlljhsdflj"

目标文件夹名称是：

"D:\Test Dest"
"D:\Test Dest-F-1108"
"D:\Test Dest-F-1111"
"D:\Test Dest-F-1120"
"D:\Test Dest-F-1125"
"D:\Test Dest-F-1130"
"D:\Test Dest-F-1135"
"D:\Test Dest-F-1209"
"D:\Test Dest-F-1223"
"D:\Test Dest-F-1252"
"D:\Test Dest-F-1254"
"D:\Test Dest-F-1307"
"D:\Test Dest-F-1309"
"D:\Test Dest-F-1317"
"D:\Test Dest-F-1351"
"D:\Test Dest-F-1414"
"D:\Test Dest-F-1426"
"D:\Test Dest-F-1428"
"D:\Test Dest-F-1432"
"D:\Test Dest-F-1433"
"D:\Test Dest-F-1434"
"D:\Test Dest-F-1435"
"D:\Test Dest-F-1451"
"D:\Test Dest-F-1476"
"D:\Test Dest-F-1526"
"D:\Test Dest-F-1528"
"D:\Test Dest-F-1532"
"D:\Test Dest-F-1533"
"D:\Test Dest-F-1554"
"D:\Test Dest-F-1565"
"D:\Test Dest-F-1576"
"D:\Test Dest-F-1623"
"D:\Test Dest-F-1626"
"D:\Test Dest-F-1649"
"D:\Test Dest-F-1654"
"D:\Test Dest-F-1659"
"D:\Test Dest-F-1671"
"D:\Test Dest-F-1709"
"D:\Test Dest-F-1712"
"D:\Test Dest-F-1799"
"D:\Test Dest-F-1800"
"D:\Test Dest-F-1801"
"D:\Test Dest-F-1882"
"D:\Test Dest-F-1883"
"D:\Test Dest-F-2000"
"D:\Test Dest-F-2001"
"D:\Test Dest-F-2002"
"D:\Test Dest-ggg-1234"
"D:\Test Dest34"
"D:\Test Dest\daddybear"

想法？

Answer 1

你的问题比较含糊，

在您要复制的标题中，
文字说移动
代码复制并删除源而不是使用 Move-Item

## Q:\Test18\SO_52866947.ps1
$SrcDir = "A:\Test\Source"
$DstDir = "A:\Test\Dest"

# Build hash table from Destination with 4digit key and Directory FullName as value
$DstHash = @{}
Get-ChildItem $DstDir -Directory | Where-Object Name -match '\d{4}'| ForEach-Object {
    $DstHash.$($Matches.Values)=$_.FullName
}

# Iterate source and check if destination key/value pair exists
Get-ChildItem $SrcDir -Directory | Where-Object Name -match '\d{4}'| ForEach-Object {
    if ($DstHash.ContainsKey($($Matches.Values))){
        "Move {0} to {1}" -f $_.FullName, $DstHash.$($Matches.Values)
        Move-Item $_.FullName -Destination $DstHash.$($Matches.Values) -Force
    } else {
        "no corresponding Destination found for: {0}" -f $_.FullName
    }
}

示例输出：
（我的内存驱动器 A 上有文件夹:)

> Q:\Test18\SO_52866947.ps1
Move A:\Test\Source-FIT-1414 to A:\Test\Dest-F-1414
Move A:\Test\Source-FIT-1576 to A:\Test\Dest-F-1576
Move A:\Test\Source-FIT-1654A to A:\Test\Dest-F-1654
Move A:\Test\Source-fred-1234 unknown to A:\Test\Dest-ggg-1234
Move A:\Test\Source-FSL-1649 to A:\Test\Dest-F-1649
Move A:\Test\Source-FV-1414 to A:\Test\Dest-F-1414
Move A:\Test\Source-FV-1654 to A:\Test\Dest-F-1654
Move A:\Test\Source-FV-1882 to A:\Test\Dest-F-1882
no corresponding Destination found for: A:\Test\Source-H-1657
no corresponding Destination found for: A:\Test\Source-H-1814
no corresponding Destination found for: A:\Test\Source-H-1924

如何使用 Powershell 通过查找每个文件夹名称中包含的匹配字符串将一个文件夹复制到另一个文件夹

How to Copy a folder to another folder by finding matching String contained in each folder name using Powershell

powershell

powershell-5.0