如何查看 SQL 中的当前选择后该值是否在 table 中再次出现

How to look if the value reoccurs in the table after current selection in SQL

我有以下数据table[CRA_feasibility_test]

atmid       CRA     monday  tuesday wednesday   thursday    friday  saturday
DA0068C1    ABC       Y      N      Y           N           N        Y

我想 select 基于我的工作日的数据 date.If 它是 Y 然后想要最接近 'Y' 即从 @ 开始的那一天是 Y日期。

我也想得到下一个

我正在做以下事情

declare @date datetime set @date ='2018-06-15' 
Select  @dateT as indentdate, DATENAME(dw,@dateT) as weekdayname,

          case when DATENAME(dw,@dateT)  ='monday'        
                                                 then  monday

                  when DATENAME(dw,@dateT)  ='tuesday'           then  
                                                            tuesday
                  when DATENAME(dw,@dateT)  ='wednesday'      then  
                                                         wednesday
                  when DATENAME(dw,@dateT)  ='Thursday'         then  
                                                       thursday
                 when DATENAME(dw,@dateT)  ='Friday'               then  
                                                   friday
                 when DATENAME(dw,@dateT)  ='Saturday'           then  
                                                 saturday       


end   feasible
from [CRA_feasibility_test] 

如果我理解正确,您可以尝试通过 cte recursive 为接下来的 7 天创建一个日历 table,然后使用 CROSS APPLYvalues make unpivot 来获得Y 最近的日期。

declare @dateT datetime
set @dateT ='2018-06-15'

;with calendar as (
  select @dateT startDt,dateadd(day,7,@dateT) endDt, 1 rn
  union all
  select dateadd(day,1,startDt) , endDt,rn +1
  from calendar
  WHERE  dateadd(day,1,startDt)<endDt
), cte as (
select 
        atmid,v.*
from CRA_feasibility_test cross apply (
    values ('monday',monday), ('tuesday',tuesday), ('wednesday',wednesday), ('thursday',thursday), ('friday',friday), ('saturday',saturday)
) v(name,flag)

)


select atmid,
    @dateT today,
    min(case when flag = 'Y' then startDt end) nextYDay,
    datename(dw,min(case when flag = 'Y' then startDt end) ) nextYname
from calendar t1 
join cte t2 on datename(dw,startDt) = t2.name
group by atmid

sqlfiddle

结果

atmid       today               nextYDay            nextYname
DA0068C1    15/06/2018 00:00:00 16/06/2018 00:00:00 Saturday