如何将字符串转换为 python 中的 ASCII 数字？

Question

我有这个代码：

str = "text"
x = str.encode('ascii')
print(x)

我明白了： b'文本'

我想得到这个： “116 101 120 116”作为字符串。我想要像 here 这样的解决方案。

Answer 1

print ([ord(c) for c in 'text'])
# [116, 101, 120, 116]

来自docs：

Given a string of length one, return an integer representing the Unicode code point of the character when the argument is a unicode object, or the value of the byte when the argument is an 8-bit string. For example, ord('a') returns the integer 97, ord(u'\u2020') returns 8224. This is the inverse of chr() for 8-bit strings and of unichr() for unicode objects. If a unicode argument is given and Python was built with UCS2 Unicode, then the character’s code point must be in the range [0..65535] inclusive; otherwise the string length is two, and a TypeError will be raised.

Answer 2

使用 map 将每个字符映射到它的 ascii 值

str1 = "text"
list(map(ord,str1))

如果需要作为字符串输出

str1 = "text"
' '.join(list(map(str,map(ord,str1))))

如何将字符串转换为 python 中的 ASCII 数字？

How can I convert string to get ASCII numbers in python?

python

ascii

encode