Date/Time Oracle 中不同行中相同字段的差异

Question

我有以下视图，我需要做的是获取具有相同 Vehicle 和 OrderCode 的每 2 条记录之间 ActionDate 字段的日期差异，我如何在 Oracle 数据库中实现此目的。

同时考虑到减去的日期应该是 模式 O - 模式 I

我需要获取差异列表，以便获得该时间的平均值。

感谢您的帮助。

Answer 1

使用 GROUP BY 并减去子查询中的日期

SELECT t.IO_SEQ, t.Vehicle, t.OrderCode, (SELECT MAX(t2.ActionDate) FROM table t2 WHERE t.IO_SEQ = t2.IO_SEQ) - (SELECT MIN(t2.ActionDate) FROM table t2 WHERE t.IO_SEQ = t2.IO_SEQ) AS ActionDiff
FROM table t
GROUP BY t.IO_SEQ, t.Vehicle, t.OrderCode

Answer 2

您可以在以下查询中使用 MAX 和 GROUP BY：

with src as 
(
  select 'O' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 16:34:35','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  union all
  select 'I' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 15:27:09','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  union all
  select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 14:03:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  union all
  select 'I' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 13:47:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  union all
  select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411185798' as OrderCode, to_date('2014-11-20 01:40:58','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  union all
  select 'I' as "MODE", 'V2987654321' as  Vehicle, '1411185798' as OrderCode, to_date('2014-11-20 00:47:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
)

select Vehicle,OrderCode, max(case when "MODE" = 'O' then ActionDate end) as MODE_O,  max(case when "MODE" = 'I' then ActionDate end) as MODE_I from src
group by Vehicle,OrderCode

Added time difference:

select Vehicle,OrderCode, max(case when "MODE" = 'O' then ActionDate end) as MODE_O,  max(case when "MODE" = 'I' then ActionDate end) as MODE_I, max(case when "MODE" = 'O' then ActionDate end) - max(case when "MODE" = 'I' then ActionDate end) as time_difference from src
group by Vehicle,OrderCode

Answer 3

你可以试试这个（没有测试所以它可能有一些语法错误）。这个想法是加入 table 本身：

select OMode.Vehicle, OMode.OrderCode, OMode.ActionDate-IMode.ActionDate 
from 
    (select Vehicle, OrderCode, ActionDate from table where Mode='O' ) OMode, 
    (select Vehicle, OrderCode, ActionDate from table where Mode='I' ) IMode

where OMode.Vehicle = IMode.Vehicle and OMode.OrderCode = IMode.OrderCode

Answer 4

您可以使用解析 LAG() OVER() 函数来获取日期之间的差异。

例如，

SQL> WITH t AS
  2  (
  3    select 'O' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 16:34:35','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  4    union all
  5    select 'I' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 15:27:09','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  6    union all
  7    select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 14:03:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  8    union all
  9    select 'I' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 13:47:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
 10    union all
 11    select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411185798' as OrderCode, to_date('2014-11-20 01:40:58','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
 12    union all
 13    SELECT 'I' AS "MODE", 'V2987654321' AS  Vehicle, '1411185798' AS OrderCode, to_date('2014-11-20 00:47:02','yyyy-mm-dd hh24:mi:ss') AS ActionDate FROM dual
 14  )
 15  SELECT "MODE",
 16    Vehicle,
 17    OrderCode,
 18    TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
 19    TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
 20    ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
 21  FROM t;

M VEHICLE     ORDERCODE  DT                  LAG_DT                    DIFF
- ----------- ---------- ------------------- ------------------- ----------
I V1234567890 1411196232 2014-11-19 15:27:09
O V1234567890 1411196232 2014-11-19 16:34:35 2014-11-19 15:27:09 .046828704
I V2987654321 1411185798 2014-11-20 00:47:02
O V2987654321 1411185798 2014-11-20 01:40:58 2014-11-20 00:47:02 .037453704
I V2987654321 1411206614 2014-11-20 13:47:02
O V2987654321 1411206614 2014-11-20 14:03:02 2014-11-20 13:47:02 .011111111

6 rows selected.

SQL>

注意： WITH 子句 用于构建 示例数据 ，在您的情况下你需要使用你实际的 table_name:

SELECT "MODE",
  Vehicle,
  OrderCode,
  TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
  TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
  ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
FROM your_table;

我放 TO_CHAR 只是为了演示目的，您想要的输出是 DIFF 列。关于MODE，您可以将其添加到过滤谓词中。

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