我的代码长度不断增加。有没有办法简化它?
My code length keeps expanding. Is there a way to simplify it?
这是我为学校写的一些代码。问题是,如果我继续添加更多 "input" 函数、使用的行数和 "and" 的数量,它会在 两个区域 变得非常长我使用的功能。 它太大了,以至于我的学校作业页面滞后。如果你想用 7 个或更多数字来做,那么它会使我的页面滞后得更多。 如何简化下面的代码?
作业:编写一个程序来输入 6 个数字。输入每个数字后,打印目前输入的最大数字。
num1 = int(input("Enter a number:"))
print ("Largest: " + str(num1) + "\n")
num2 = int(input("Enter a number:"))
if (num1 > num2):
print ("Largest: " + str(num1) + "\n")
else:
print ("Largest: " + str(num2) + "\n")
num3 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3):
print ("Largest: " + str(num2) + "\n")
else:
print ("Largest: " + str(num3) + "\n")
num4 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3 and num1 > num4):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3 and num2 > num4):
print ("Largest: " + str(num2) + "\n")
elif (num3 > num4):
print ("Largest: " + str(num3) + "\n")
else:
print ("Largest: " + str(num4) + "\n")
num5 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3 and num1 > num4 and num1 > num5):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3 and num2 > num4 and num2 > num5):
print ("Largest: " + str(num2) + "\n")
elif (num3 > num4 and num3 > num5):
print ("Largest: " + str(num3) + "\n")
elif (num4 > num5):
print ("Largest: " + str(num4) + "\n")
else:
print ("Largest: " + str(num5) + "\n")
num6 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3 and num1 > num4 and num1 > num5 and num1 > num6):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3 and num2 > num4 and num2 > num5 and num2 > num6):
print ("Largest: " + str(num2) + "\n")
elif (num3 > num4 and num3 > num5 and num3 > num6):
print ("Largest: " + str(num3) + "\n")
elif (num4 > num5 and num4 > num6):
print ("Largest: " + str(num4) + "\n")
elif (num5 > num6):
print ("Largest: " + str(num5) + "\n")
else:
print ("Largest: " + str(num6) + "\n")
您可以只将数字存储在变量中,并在用户输入更大的数字时覆盖它。
awesome_number = 0
while True: # Always loop unless we break the loop.
userInput = int(input("Enter a number:")) # Your input phrase
# Compare values, evaluates to True if the user input is greater
if userInput > awesome_number:
awesome_number = userInput # Overwrite if compare evaluates to True
# Print using the .format method to dynamically insert the greatest
# number
print("So far, the biggest number you've entered is {}".format(awesome_number))
如果您想在 n 次输入后停止,您可以添加一个简单的计数器来计算迭代次数。
awesome_number = 0
counter = 0
while True: # Always loop unless we break the loop.
userInput = int(input("Enter a number:")) # Your input phrase
# Compare values, evaluates to True if the user input is greater
if userInput > awesome_number:
awesome_number = userInput # Overwrite if compare evaluates to True
# Print using the .format method to dynamically insert the greatest
# number
print("So far, the biggest number you've entered is {}".format(awesome_number))
# Increment the counter
counter = counter + 1
if counter == 500: # Arbitrary number to end on
break
这可以在没有任何列表或特殊语法的情况下完成,只要您使用一个简单的循环 运行 正文六次即可:
largest = None
for _ in range(6):
number = int(input('Enter a number: '))
if largest is None or number > largest:
largest = number
print('Largest: {}\n'.format(largest))
如果由于某种原因不允许您使用循环,您可以通过手动展开循环来获得相同的结果:
largest = int(input('Enter a number: '))
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
这是我为学校写的一些代码。问题是,如果我继续添加更多 "input" 函数、使用的行数和 "and" 的数量,它会在 两个区域 变得非常长我使用的功能。 它太大了,以至于我的学校作业页面滞后。如果你想用 7 个或更多数字来做,那么它会使我的页面滞后得更多。 如何简化下面的代码?
作业:编写一个程序来输入 6 个数字。输入每个数字后,打印目前输入的最大数字。
num1 = int(input("Enter a number:"))
print ("Largest: " + str(num1) + "\n")
num2 = int(input("Enter a number:"))
if (num1 > num2):
print ("Largest: " + str(num1) + "\n")
else:
print ("Largest: " + str(num2) + "\n")
num3 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3):
print ("Largest: " + str(num2) + "\n")
else:
print ("Largest: " + str(num3) + "\n")
num4 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3 and num1 > num4):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3 and num2 > num4):
print ("Largest: " + str(num2) + "\n")
elif (num3 > num4):
print ("Largest: " + str(num3) + "\n")
else:
print ("Largest: " + str(num4) + "\n")
num5 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3 and num1 > num4 and num1 > num5):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3 and num2 > num4 and num2 > num5):
print ("Largest: " + str(num2) + "\n")
elif (num3 > num4 and num3 > num5):
print ("Largest: " + str(num3) + "\n")
elif (num4 > num5):
print ("Largest: " + str(num4) + "\n")
else:
print ("Largest: " + str(num5) + "\n")
num6 = int(input("Enter a number:"))
if (num1 > num2 and num1 > num3 and num1 > num4 and num1 > num5 and num1 > num6):
print ("Largest: " + str(num1) + "\n")
elif (num2 > num3 and num2 > num4 and num2 > num5 and num2 > num6):
print ("Largest: " + str(num2) + "\n")
elif (num3 > num4 and num3 > num5 and num3 > num6):
print ("Largest: " + str(num3) + "\n")
elif (num4 > num5 and num4 > num6):
print ("Largest: " + str(num4) + "\n")
elif (num5 > num6):
print ("Largest: " + str(num5) + "\n")
else:
print ("Largest: " + str(num6) + "\n")
您可以只将数字存储在变量中,并在用户输入更大的数字时覆盖它。
awesome_number = 0
while True: # Always loop unless we break the loop.
userInput = int(input("Enter a number:")) # Your input phrase
# Compare values, evaluates to True if the user input is greater
if userInput > awesome_number:
awesome_number = userInput # Overwrite if compare evaluates to True
# Print using the .format method to dynamically insert the greatest
# number
print("So far, the biggest number you've entered is {}".format(awesome_number))
如果您想在 n 次输入后停止,您可以添加一个简单的计数器来计算迭代次数。
awesome_number = 0
counter = 0
while True: # Always loop unless we break the loop.
userInput = int(input("Enter a number:")) # Your input phrase
# Compare values, evaluates to True if the user input is greater
if userInput > awesome_number:
awesome_number = userInput # Overwrite if compare evaluates to True
# Print using the .format method to dynamically insert the greatest
# number
print("So far, the biggest number you've entered is {}".format(awesome_number))
# Increment the counter
counter = counter + 1
if counter == 500: # Arbitrary number to end on
break
这可以在没有任何列表或特殊语法的情况下完成,只要您使用一个简单的循环 运行 正文六次即可:
largest = None
for _ in range(6):
number = int(input('Enter a number: '))
if largest is None or number > largest:
largest = number
print('Largest: {}\n'.format(largest))
如果由于某种原因不允许您使用循环,您可以通过手动展开循环来获得相同的结果:
largest = int(input('Enter a number: '))
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))
number = int(input('Enter a number: '))
if number > largest:
largest = number
print('Largest: {}\n'.format(largest))