执行一个查询时出现错误语法

Question

我需要创建 table 并且我这样做了：

CREATE TABLE "home" (
  "id" int(11) NOT NULL AUTO_INCREMENT,
  "address" varchar(200) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  PRIMARY KEY ("id")
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 COLLATE=latin1_bin;

当我执行此查询时出现此错误：

Errore SQL [1064] [42000]: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"causali" (
  "id" int(11) NOT NULL AUTO_INCREMENT,
  "address" va' at line 1
  You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"home" (
  "id" int(11) NOT NULL AUTO_INCREMENT,
  "adddress" va' at line 1

谁能帮帮我？

Answer 1

MySQL 不喜欢 table / 列 / 别名上的双引号，直到我们启用 ANSI_QUOTES 模式。

Treat " as an identifier quote character (like the ` quote character) and not as a string quote character. You can still use backticks to quote identifiers with this mode enabled. With ANSI_QUOTES enabled, you cannot use double quotation marks to quote literal strings because they are interpreted as identifiers.

此模式默认禁用。现在，您可以在它们周围使用反引号，或者不使用双引号（除非是 Reserved keyword，否则您将不得不在其周围使用反引号）。

CREATE TABLE home (
  id int(11) NOT NULL AUTO_INCREMENT,
  address varchar(200) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  PRIMARY KEY (id)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 COLLATE=latin1_bin;

执行一个查询时出现错误语法

I obtain a error syntax when I exceute one query

mysql

sql

create-table