child 组件 React Native 中的关闭模式

Question

我有两个 React Native 组件，我无法从我的 child 组件关闭模态。

ListTrips - Parent

ModalAddTrip - Child

ListTrips.js

import ModalAddTrip from './ModalAddTrip';
....
....
this.state = {
    isModalAddTripVisible: false
} 
....
handleDismissModalAddTrip = () => {
    this.setState({ isModalAddTripVisible: false });
};

closeModal() {
    this.refs.ModalAdd.handleDismissModalAddTrip();
}
....

<ModalAddTrip
    ref="ModalAdd"
    isVisible={this.state.isModalAddTripVisible}
    onBackDropPress={this.handleDismissModalAddTrip}
    closeModal={() => this.closeModal()}
    onRequestClose={this.handleDismissModalAddTrip}
/>

ModalAddTrip.js

<Modal
    isVisible={isVisible}
    onBackdropPress={onBackDropPress}
    closeModal={this.props.child}
>
<Button
    style={{ fontSize: 18, color: 'white' }}
    containerStyle={{
        padding: 8,
        marginLeft: 70,
    }}
    onPress={this.closeModal}
>

打开模式后无法关闭它。我知道它与 referencing/props 有关，但我已经弄乱了它几个小时，但我无处可去。我尝试了一些类似 this.props.closeModal; 的方法，同时将 ref 切换到 child 组件，但它也没有用。在 ModalAddTrip 的一个函数中，但这也不起作用。

非常感谢任何帮助。谢谢

Answer 1

ModalAddTrip.js

  _toggleModal = () =>
      this.setState({ isVisible: !this.state.isVisible });
  ....

  render() { 
  ....
   <Modal
    isVisible={isVisible}
    onBackdropPress={onBackDropPress}
  >
      <Button
            style={{ fontSize: 18, color: 'white' }}
            containerStyle={{
              padding: 8,
              marginLeft: 70,
            }}
            onPress={this._toggleModal} >
</Modal>

Answer 2

这是我用来处理模态的解决方案。

export default class MyModal extends React.Component<Props, State>{

  constructor(props: Props){
    super(props);
    this.state = {
      visible: false,
    }
  }

  // Use this method to toggle the modal !
  toggleModal = () => {
    this.setState({visible: !this.state.visible});
  }


  render(){
    return(
      <Modal
      isVisible={this.state.visible}
      hideModalContentWhileAnimating
      onBackdropPress={() => {
        this.toggleModal();
      }}
      useNativeDriver
      >
        <View style={{backgroundColor: "white", padding: 5}}>
        </View>
      </Modal>
    );
  }
}

如果我在它后面按下，模态框将关闭 -> 它可以自行关闭。

现在要从父组件管理它，只需从您的模式中获取一个引用即可：

  <MyModal 
    ref={ref => {
      this.myModal = ref;
    }}
  />

并且您可以从父组件切换它：

toggleMyModal = () => {
    if(this.myModal){
      this.myModal.toggleModal();
    }
  }

如果你成功了请告诉我:)

Answer 3

//对我来说效果很好//

模态EXAMPLE.JS

...
import Child from "./components/Child.js"

const ModalExample = () => {    

  const [modalVisible, setModalVisible] = useState(true)

  return(
    <Modal visible={ModalVisible}>
      <Child closeModal={()=>setModalVisible(false)}/>
    </Modal>
  )
}
export default ModalExample

CHILD.JS

...
const Child = (closeModal) => {
  render(
    <Button title="close" onPress={closeModal.closeModal}/>
  )
}
export default Child

child 组件 React Native 中的关闭模式

Closing modal in child component React Native

modal-dialog

ref

react-native

react-props