检查点击是否在图形对象内 [Python 图形模块]

Checking if clicks are within a graphic object [Python Graphics Module]

这是我正在使用的模块:http://mcsp.wartburg.edu/zelle/python/graphics/graphics.pdf

我想看看用户的点击是否在一个形状内。我使用了 in 运算符,但我知道这是不正确的。下面是我的代码块:

win = GraphWin("Click Speed", 700, 700)

theTarget = drawTarget(win, random.randrange(0,685), random.randrange(0,685))

while theTarget in win:
    click = win.getMouse()
    if click in theTarget:
        print("Good job")

我省略了绘制目标形状的代码,因为它很长而且没有必要。 是一个动圈

我正在使用 while 循环,这样我就可以不断获得用户的点击。

如何使用 getMouse() 命令检查用户的点击是否在指定的目标形状中?

我以后要用这个来做更抽象的形状(不是简单的圆圈)。

圆形

对于一个简单的圆圈,可以通过距离公式判断鼠标是否在里面。例如:

# checks whether pt1 is in circ
def inCircle(pt1, circ):

    # get the distance between pt1 and circ using the
    # distance formula
    dx = pt1.getX() - circ.getCenter().getX()
    dy = pt1.getY() - circ.getCenter().getY()
    dist = math.sqrt(dx*dx + dy*dy)

    # check whether the distance is less than the radius
    return dist <= circ.getRadius()

def main():
    win = GraphWin("Click Speed", 700, 700)

    # create a simple circle
    circ = Circle(Point(350,350),50)
    circ.setFill("red")
    circ.draw(win)

    while True:
        mouse = win.getMouse()
        if inCircle(mouse,circ):
            print ("Good job")

main()

椭圆形

对于更高级的椭圆示例,我们需要使用找到的公式 here。这是实现的功能:

def inOval(pt1, oval):

    # get the radii
    rx = abs(oval.getP1().getX() - oval.getP2().getX())/2
    ry = abs(oval.getP1().getY() - oval.getP2().getY())/2

    # get the center
    h = oval.getCenter().getX()
    k = oval.getCenter().getY()

    # get the point
    x = pt1.getX()
    y = pt1.getY()

    # use the formula
    return (x-h)**2/rx**2 + (y-k)**2/ry**2 <= 1

多边形

对于任意形状的多边形,我们需要参考this。我已将其转换为 python 等价物。检查 link 看看它为什么有效,因为老实说我不确定

def inPoly(pt1, poly):

    points = poly.getPoints()
    nvert = len(points) #the number of vertices in the polygon

    #get x and y of pt1
    x = pt1.getX()
    y = pt1.getY()

    # I don't know why this works
    # See the link I provided for details
    result = False
    for i in range(nvert):

        # note: points[-1] will give you the last element
        # convenient!
        j = i - 1

        #get x and y of vertex at index i
        vix = points[i].getX()
        viy = points[i].getY()

        #get x and y of vertex at index j
        vjx = points[j].getX()
        vjy = points[j].getY()

        if (viy > y) != (vjy > y) and (x < (vjx - vix) * (y - viy) / (vjy - viy) + vix):
            result = not result

    return result