弹出 Window 去第一或第二

Popup Window to go first or second

我正在编写一个简单的井字游戏,在每次输赢后,我希望玩家选择他们是想先走还是后走(X 或 0)。获取此信息的最佳策略是什么?

您可以显示一个 AlertDialog 来为 0 和 X 设置 RadioButton,这是给玩家提供选项的简单且推荐的方法。

参考示例代码:

AlertDialog playerDialog;

// Strings to Show In Dialog with Radio Buttons
final CharSequence[] items = {" Zero "," Cross "};

 // Creating and Building the Dialog 
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Select Your Player");
builder.setSingleChoiceItems(items, -1, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int item) {
switch(item)
{
case 0:
// Your code when first option selected
break;
case 1:
// Your code when 2nd  option selected
break;
}
playerDialog.dismiss();    
}
});
playerDialog = builder.create();
playerDialog.show();