检查字符串是否包含数字、字母和空格

Question

我正在尝试提出一个断言语句来检查非空字符串 s 是否包含字母数字字符和空格：

    assert s.isalnum()

我知道如果有空格，这将 return 错误，因为它会检查每个字符是字母还是数字。我该如何解决这个问题？

编辑：为了澄清起见，我正在尝试创建一个断言语句来检查非空字符串是否包含字母数字字符 and/or 空格。例如，“a 4 bc”和 "ab" 都应该 return True。

Answer 1

您可以使用 all，检查每个字符是否为字母数字或 space:

text = "apple and 123"

result = all(c.isalnum() or c.isspace() for c in text)
print(result)

text = "with ."

result = all(c.isalnum() or c.isspace() for c in text)
print(result)

输出

True
False

如果它最多包含spaces 和个字母数字字符，你可以这样做：

def only_alnum_and_spaces(t):
    counts = {"spaces" : 0, "alnums": 0}
    for c in t:
        if c.isalnum():
            counts["alnums"] += 1
        elif c.isspace():
            counts["spaces"] += 1
        else:
            return False
    return counts["alnums"] > 0 and counts["spaces"] > 0

print(only_alnum_and_spaces("apple and 123"))
print(only_alnum_and_spaces("with ."))
print(only_alnum_and_spaces("appleand123"))

输出

True
False
False

另请注意，如@Chris_Rands所述，此 .isspace 将制表符视为白色spaces。

Answer 2

您可以删除空格进行测试：

assert s.replace(" ","").isalnum()

Answer 3

这是一种方式

def customIsAlnum(String[] words):
    if(len(words) > 1):
       for(word in words):
           if(!word.isalnum()):
               return false
    else:
        return false
    return true


String str = "chelsea scored 3 goals"
String[] words = str.split()
print customIsAlnum(words)

Answer 4

也许这就是您想要的：

assert any(substr.issapce() or substr.isdigit() or substr.isalpha() for substr in s)

测试字符串：

>>> s1 = '123 45    abc  67  d'
>>> s2 = '123456'
>>> s3 = 'abcd'
>>> s4 = ':?--==++'

检查字符串是否包含space:

>>> def hasAnySpace(str):
...   return ' ' in str
...
>>> hasAnySpace(s1)
True
>>> hasAnySpace(s2)
False
>>> hasAnySpace(s3)
False
>>> hasAnySpace(s4)
False

检查一个字符串是否包含任何数字，可以使用any function and str.isdigit函数：

>>> def hasAnyDigit(str):
...   return any (substr.isdigit() for substr in str)
...
>>> hasAnyDigit(s1)
True
>>> hasAnyDigit(s2)
True
>>> hasAnyDigit(s3)
False
>>> hasAnyDigit(s4)
False

检查一个字符串是否包含任何字母字符，可以使用any function and str.isalpha函数：

>>> def hasAnyAlpha(str):
...   return any(substr.isalpha() for substr in str)
...
>>> hasAnyAlpha(s1)
True
>>> hasAnyAlpha(s2)
False
>>> hasAnyAlpha(s3)
True
>>> hasAnyAlpha(s4)
False

检查字符串是否包含任何数字，或任何字母字符或任何space:

>>> def hasAnyAlNumSpace(str):
...   return any(substr.isalpha() or substr.isdigit() or substr.isspace() for substr in str)
...
>>> hasAnyAlNumSpace(s1)
True
>>> hasAnyAlNumSpace(s2)
True
>>> hasAnyAlNumSpace(s3)
True
>>> hasAnyAlNumSpace(s4)
False

如果要使用assert语句，可以任意组合使用：

>>> assert hasAnySpace(s1) or hasAnyDigit(s1) or hasAnyAlpha(s1) 
>>> assert hasAnySpace(s2) or hasAnyDigit(s2) or hasAnyAlpha(s2)
>>> assert hasAnySpace(s3) or hasAnyDigit(s3) or hasAnyAlpha(s3)
>>> assert hasAnySpace(s4) or hasAnyDigit(s4) or hasAnyAlpha(s4)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AssertionError
>>>
>>> assert hasAnySpace(s1)
>>> assert hasAnySpace(s2)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AssertionError
>>>
>>> assert hasAnyAlNumSpace(s1)
>>> assert hasAnyAlNumSpace(s2)
>>> assert hasAnyAlNumSpace(s3)
>>> assert hasAnyAlNumSpace(s4)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AssertionError

当然，如果你不喜欢这些方法，你可以像这样简单地使用断言：

assert ' ' in s1    
assert any(substr.isdigit() for substr in s1)
assert any(substr.isalpha() for substr in s1)
assert (' ' in s1) or any(substr.isdigit() or substr.isalpha() for substr in s1)
assert any(substr.issapce() or substr.isdigit() or substr.isalpha() for substr in s1)

检查字符串是否包含数字、字母和空格

Check if string has numbers, letters and spaces

python

assert