JAVA

Question

我有一串用逗号分隔的值，我将它们转换成一个数组，然后我将使用它来创建一个二维数组。创建循环以将数据从第一个数组添加到二维数组时，它会重复数据。

我得到的输出是：

4428,40,401,610,2016,3821,31,347,572,2015,4381,38,341,520,2014,2536,17,193,290,2013,4295,39,371,552,2012,4643,45,343,502,2011,3922,28,312,475,2010,4434,30,350,541,2009,4038,28,341,536,2008,218,1,20,28,2007,46,0,6,15,2006,65,0,9,16,2005,4428,40,401,610,2016,3821,31,347,572,2015,4381,38,341,520,2014,2536,17,193,290,2013,4295,39,371,552,2012,4643,45,343,502,2011,3922,28,312,475,2010,4434,30,350,541,2009,4038,28,341,536,2008,218,1,20,28,2007,46,0,6,15,2006,65,0,9,16,2005,4428,40,401,610,2016,3821,31,347,572,2015,4381,38,341,520,2014,2536,17,193,290,2013,4295,39,371,552,2012,4643,45,343,502,2011,3922,28,312,475,2010,4434,30,350,541,2009,4038,28,341,536,2008,218,1,20,28,2007,46,0,6,15,2006,65,0,9,16,2005,4428,40,401,610,2016,3821,31,347,572,2015,4381,38,341,520,2014,2536,17,193,290,2013,4295,39,371,552,2012,4643,45,343,502,2011,3922,28,312,475,2010,4434,30,350,541,2009,4038,28,341,536,2008,218,1,20,28,2007,46,0,6,15,2006,65,0,9,16,2005,4428,40,401,610,2016,3821,31,347,572,2015,4381,38,341,520,2014,2536,17,193,290,2013,4295,39,371,552,2012,4643,45,343,502,2011,3922,28,312,475,2010,4434,30,350,541,2009,4038,28,341,536,2008,218,1,20,28,2007,46,0,6,15,2006,65,0,9,16,2005

正确的输出应该是：

4428,40,401,610,2016,3821,31,347,572,2015,4381,38,341,520,2014,2536,17,193,290,2013,4295,39,371,552,2012,4643,45,343,502,2011,3922,28,312,475,2010,4434,30,350,541,2009,4038,28,341,536,2008,218,1,20,28,2007,46,0,6,15,2006,65,0,9,16,2005

预期结果：

{{4428,40,401,610,2016}

{3821,31,347,572,2015}

{4381,38,341,520,2014}

...} and so on, every 5

我将数组添加到二维数组的代码如下：

 {String[] columns = {"Yards","Touchdowns","Attempts","Incompletions","Year"};



String[] data1 = results1.split(",");

Object [][] data11 = new Object[columns.length][data1.length];
for(int i = 0; i<columns.length;i++){
    for(int j = 0; j<data1.length;j++){
    data11[i][j] = data1[j];
    //System.out.print(data11[i][j]+",");
}
}}

编辑：解决方案！

Object [][] data11 = new Object[data1.length/columns.length][columns.length];
int column = -1;
for(int j = 0; j<data1.length;j++){
    if(j % columns.length == 0) column = column+1;
            data11[column][j % 5] = data1[j];
}

Answer 1

你还循环第一个数组(i)，所以他会重复。就这么写：

 data11[0][j] = data1[j];

或者甚至根本不执行第一个循环，具体取决于您的需要。假设你的输出，你只想填充数组的第一个位置（0）。

Answer 2

也许这对你有用：

Object [][] data11 = new Object[columns.length][data1.length / 5];
int column = -1;
for(int j = 0; j<data1.length;j++){
    if(j % 5 == 0) column = column + 1
    data11[j % 5][column] = data1[j];
}

注意矩阵大小和分配也发生了变化。没试过，也许你可以做一个更漂亮的版本。希望对您有所帮助！

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