如何使用地址（指针）从 lldb 调用 swift 函数？

Question

我正在玩 lldb 并尝试调用我的 swift 静态函数。我能够在图像中找到它的详细信息，但是我不知道如何调用它并传递参数。

我的输出：

(lldb) image lookup -vs $S5project19ViewControllerUtilsC07setRootbC010storyboard13withAnimationySo12UIStoryboardC_SbtFZ
1 symbols match '$S5project19ViewControllerUtilsC07setRootbC010storyboard13withAnimationySo12UIStoryboardC_SbtFZ' in /Users/user/Library/Developer/CoreSimulator/Devices/DC7A5199-424E-4E38-A8A8-CB99C7D8CF82/data/Containers/Bundle/Application/BE7BB249-DB64-4228-B64E-EB430BCCE29E/project.app/project:
        Address: project[0x00000002000fc970] (project.__TEXT.__text + 1027840)
        Summary: project`static project.ViewControllerUtils.setRootViewController(storyboard: __C.UIStoryboard, withAnimation: Swift.Bool) -> () at ViewControllerUtils.swift:7
         Module: file = "/Users/user/Library/Developer/CoreSimulator/Devices/DC7A5199-424E-4E38-A8A8-CB99C7D8CF82/data/Containers/Bundle/Application/BE7BB249-DB64-4228-B64E-EB430BCCE29E/project.app/project", arch = "x86_64"
    CompileUnit: id = {0x00000000}, file = "/Users/user/mobile/company/iOS/project/project/Utils/ViewControllerUtils.swift", language = "swift"
       Function: id = {0x7700000075}, name = "static project.ViewControllerUtils.setRootViewController(storyboard: __C.UIStoryboard, withAnimation: Swift.Bool) -> ()", mangled = "$S5project19ViewControllerUtilsC07setRootbC010storyboard13withAnimationySo12UIStoryboardC_SbtFZ", range = [0x000000010bd0c780-0x000000010bd0c82e)
       FuncType: id = {0x7700000075}, byte-size = 8, decl = ViewControllerUtils.swift:7, compiler_type = "(UIKit.UIStoryboard, Swift.Bool) -> ()
"
         Blocks: id = {0x7700000075}, range = [0x10bd0c780-0x10bd0c82e)
      LineEntry: [0x000000010bd0c780-0x000000010bd0c79d): /Users/user/mobile/company/iOS/project/project/Utils/ViewControllerUtils.swift:7
         Symbol: id = {0x00002a71}, range = [0x000000010ac0c780-0x000000010ac0c830), name="static project.ViewControllerUtils.setRootViewController(storyboard: __C.UIStoryboard, withAnimation: Swift.Bool) -> ()", mangled="$S5project19ViewControllerUtilsC07setRootbC010storyboard13withAnimationySo12UIStoryboardC_SbtFZ"
       Variable: id = {0x6600000092}, name = "storyboard", type = "UIKit.UIStoryboard", location =  DW_OP_fbreg(-16), decl = ViewControllerUtils.swift:7
       Variable: id = {0x66000000a0}, name = "withAnimation", type = "Swift.Bool", location =  DW_OP_fbreg(-24), decl = ViewControllerUtils.swift:7
       Variable: id = {0x66000000ae}, name = "self", type = "@thick project.ViewControllerUtils.Type", location =  DW_OP_fbreg(-32), decl = ViewControllerUtils.swift:7

源代码：

final class ViewControllerUtils {
    static func setRootViewController(storyboard: UIStoryboard, withAnimation: Bool) {
        setRootViewController(window: UIApplication.shared.keyWindow, storyboard: storyboard, withAnimation: withAnimation)
    }
}

我知道我可以切换到 Swift 并调用这样的东西：

expression -l swift -O -- ViewControllerUtils.setRootViewController(storyboard: UIKit.UIStoryboard(name: "Main", bundle: nil), withAnimation: true)

但我想学习如何使用它的地址或符号调用一个函数，而不像上面那样引用特定的class。

Answer 1

我找到了解决办法。

取地址范围：Symbol: id = {0x00002a71}, range = [0x000000010ac0c780-0x000000010ac0c830) 这个：0x000000010ac0c780.
导入 UIKit (lldb) po import UIKit
创建 Storyboard：

(lldb) p UIStoryboard(name: "Main", bundle: nil)  
(UIStoryboard) $R2 = 0x00006000006c8200 {  
  ObjectiveC.NSObject = {  
    isa = UIStoryboard  
  }  
}

将原始地址转换为函数并使用创建的 Storyboard 变量调用它 $R2:
(lldb) po unsafeBitCast(0x000000010ac0c780, to: (@convention(c)(UIKit.UIStoryboard, Bool) -> ()).self)($R2, true)

在这里您还可以阅读导入 C 函数的有趣示例：

如何使用地址（指针）从 lldb 调用 swift 函数？

How to invoke swift function from lldb using address (pointer)?

debugging

objective-c

lldb

swift