我如何为这个 JAVA 项目构建我的测试器 class？

Question

所以早些时候我弄清楚了 EmployeeNames 部分是如何分配的，或者至少我认为我做到了。这是 EmployeeNames 代码：

   public static String[] convertName(String[] names) {
      for (int i=0; i<10; i++) {
         names[i] = names[i].substring(names[i].length() - 2, names[i].length());
        }
      return names;

但我基本上停留在测试程序代码上。我知道我想要什么，但它不起作用。谁能帮我吗？几个小时以来，我一直在挠头。

public static void main(String args[]) {
      /*Scanner scan = new Scanner(System.in);
      System.out.println("Enter 10 last names.");
      String input = scan.nextLine();
      */ (Ignore this, I wanted to try doing inputs, but couldn't even figure out how to work with them properly so I typed up sample last names for this.)

     String[] lastName = {"Jones", "Roberts", "Lee", "Chang", "Patel", "Park", "Anderson", "Liu", "Smith", "Lopez"};
     System.out.println(convertName(lastName));
    }

我喜欢看到对我的代码或伪代码结构的修改，因为它可以帮助我最好地认识到我的错误，但任何帮助都是至关重要的！提前谢谢你。

Answer 1

您犯了一些小错误，这是根据您的要求工作的代码 -

class EmployeeNames {
    public static String[] convertName(String[] lastNames) {
        String[] formattedNames = new String[lastNames.length];
        for (int i = 0; i < lastNames.length; i++) {
            formattedNames[i] = lastNames[i].substring(lastNames[i].length() - 1) + "."
                    + lastNames[i].substring(lastNames[i].length() - 2, lastNames[i].length() - 1) + "." + lastNames[i];

        }
        return formattedNames;
    }

}

public class EmployeeNamesTester {

    public static void main(String[] args) {
        String[] lastNames = { "Jones", "Roberts", "Lee", "Chang", "Patel", "Park", "Anderson", "Liu", "Smith",
                "Lopez" };
        String[] formattedNames = EmployeeNames.convertName(lastNames);
        for (String formattedName : formattedNames) {
            System.out.println(formattedName);
        }

    }

}

Output:
s.e.Jones
s.t.Roberts
e.e.Lee
g.n.Chang
l.e.Patel
k.r.Park
n.o.Anderson
u.i.Liu
h.t.Smith
z.e.Lopez

希望对您有所帮助！

Answer 2

你在题目中犯了一些逻辑错误。

public static String[] convertName(String[] names) {
        String newNames[]=new String[names.length];
          for (int i=0; i<names.length; i++) {
             newNames[i] = names[i].substring(names[i].length() - 2, names[i].length());
            }
          return newNames; 
    }

在上面的方法中，我只是创建了新数组和 return 具有修改值的新数组。

并且在 Main 方法中使用了以下代码-

public static void main(String[] args)  {
    String[] lastName = {"Jones", "Roberts", "Lee", "Chang", "Patel", "Park", "Anderson", "Liu", "Smith", "Lopez"};

            String [] result= convertName(lastName);
            for(int i=0;i<result.length;i++){
                String lastNames=result[i];
                if(lastNames !=null){
                    System.out.println(lastNames.toUpperCase().charAt(1)+"."+lastNames.toUpperCase().charAt(0)+". "+lastName[i]);
                }
            }

}

希望对您有所帮助！！

我如何为这个 JAVA 项目构建我的测试器 class？

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