MYSQL 在记录输入时自动解密我的密码
MYSQL is automatically decrypting my password upon record entry
我有一个脚本可以将电子邮件地址和密码添加到 table。我首先搜索一下 table 中是否存在电子邮件地址。如果是这样,我会给出错误消息。如果没有,我添加记录。
然后,使用 mysqli_insert_id(),我 运行 另一个查询来更新我刚添加的记录,用 md5 加密密码。
但是每次我运行它时,都会添加记录,但密码不会更新为md5 版本的密码。我已经回显了查询,它表明它应该使用加密更新密码,但事实并非如此。有什么想法吗?
<?php
session_start();
error_reporting(E_ALL);
if (array_key_exists("submit", $_POST)) {
$link = mysqli_connect("localhost", "eits_Admin", "WebSpinner1", "EITS_Sandbox");
if (!$link) {
die("Database connection error");
}
$error = '';
if (!$_POST['email']) {
$error .= "<br/>An email address is required";
}
if (!$_POST['password']) {
$error .= "<br/>A password is required";
}
if ($error != "") {
$error = "There were errors in your form - ".$error;
} else {
$query = "select id from secretdiary
where email = '".mysqli_real_escape_string($link, $_POST['email'])
."' limit 1";
// echo $query;
$result = mysqli_query($link, $query);
if (mysqli_num_rows($result) > 0) {
$error = "That email address is not available.";
} else {
$query = "insert into secretdiary
(email,password)
values ('" . mysqli_real_escape_string($link, $_POST['email'])
. "', '"
. mysqli_real_escape_string($link, $_POST['password']) . "')";
if (!mysqli_query($link, $query)) {
$error = "Could not sign you up at this time. Please try again later.";
} else {
$encPass = md5(md5(mysqli_insert_id($link)) . $_POST['password']);
$query = "update secretdiary
set password = '" . $encPass
. "' where id = " . mysqli_insert_id($link) . " limit 1";
echo $query;
$result = mysqli_query($link,$query);
echo "Sign up successful.";
}
}
}
}
?>
<div id="error"><? echo $error; ?></div>
<form method="post">
<input type="email" name="email" placeholder= "Your Email">
<input type="password" name="password" placeholder="Password">
<input type="checkbox" name="stayLoggedIn" value=1>
<input type="submit" name="submit" value="Sign Up!">
</form>
对于一个相对简单的过程,您有很多代码行。就个人而言,您的表单错误处理,例如它是否为空(在这种情况下)可以通过在每个 HTML 表单输入元素的末尾添加 required
来补救(这就是我要做的)
其次,md5 对散列密码不安全(你散列密码而不是加密它)
第三,这是一种使用 Bcrypt 从表单中散列密码的方法,这比使用 md5 散列法要好得多。因此,在 like counting the usernames and if row > 0 die('username exists)
使用 PDO
的基础上的完整代码示例之前,请执行您需要执行的任何错误检查
检查用户登录时只需使用 password_verify()
函数即可
整洁的代码可以帮助 SO 上的人了解您的问题所在,并且通常更易于阅读。我知道您可能只是在寻找“完成工作”的东西,但它可以在调试时帮助您,在您寻求帮助时帮助我们。
我将为您提供一种比您的方法更安全的方法。
index.php
<form method="post" id="regform" action="register.php">
<input type="text" name="username" placeholder="Enter your email Address"required/>
<input type="password" name="password" placeholder="Enter your password" required/>
<input type="submit" class="indexbttn" id="indexbttn" name="enter"value="enter"/>
</form>
connect.php
<?php
$servername = "localhost";
$dbusername = "root";
$dbpassword = "root";
$dbname = "fyp";
try{
$pdo = new PDO("mysql:host=$servername;dbname=$dbname",$dbusername, $dbpassword);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e)
{
print "Error! Unable to connect: " . $e->getMessage() . "<br/>";
die();
}
?>
register.php
<?php
session_start();
require_once ('connect.php');
error_reporting(E_ALL);
ini_set('display_errors', 1);
if(isset($_POST['enter'])){
$username = !empty($_POST['username']) ? trim($_POST['username']) : null;
$pass = !empty($_POST['password']) ? trim($_POST['password']) : null;
$check (!filter_var($_POST['username'], FILTER_VALIDATE_EMAIL));
$cnt = "SELECT COUNT(username) AS num FROM users WHERE username = :username";
$stmt = $pdo->prepare($cnt);
$stmt->bindValue(':username', $username);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
if($row['num'] > 0){
die('That username already exists!');
}
$passHash = password_hash($pass, PASSWORD_BCRYPT, array("cost" => 12));
$insrt = "INSERT INTO users (username, password) VALUES (:username, :password)";
$stmt = $pdo->prepare($insrt);
$stmt->bindValue(':username', $username);
$stmt->bindValue(':password', $passHash);
$result = $stmt->execute();
if($result){
header( "refresh:5;url=index.php" );
echo 'You will be redirected in 5 seconds. If not, click <a href="index.php">here</a>.';
}
}
?>
login.php
<?php
session_start();
require("connect.php");
if(isset($_POST['enter'])){
$username = !empty($_POST['username']) ? trim($_POST['username']) : null;
$pass = !empty($_POST['password']) ? trim($_POST['password']) : null;
$rtrv = "SELECT username, password, userid FROM users WHERE username = :username";
$stmt = $pdo->prepare($rtrv);
//Bind value.
$stmt->bindValue(':username', $username);
//Execute.
$stmt->execute();
//Fetch row.
$user = $stmt->fetch(PDO::FETCH_ASSOC);
//If $row is FALSE.
if($user === false){
//Could not find a user with that username!
die('Incorrect username');
}
else{
$validPassword = password_verify($pass, $user['password']);
if($validPassword){
$_SESSION['user_id'] = $user['username'];
$_SESSION['logged_in'] = time();
header( "Location: /protected.php" );
die();
} else{
die('Wrong password!');
}
}
}
?>
我有一个脚本可以将电子邮件地址和密码添加到 table。我首先搜索一下 table 中是否存在电子邮件地址。如果是这样,我会给出错误消息。如果没有,我添加记录。
然后,使用 mysqli_insert_id(),我 运行 另一个查询来更新我刚添加的记录,用 md5 加密密码。
但是每次我运行它时,都会添加记录,但密码不会更新为md5 版本的密码。我已经回显了查询,它表明它应该使用加密更新密码,但事实并非如此。有什么想法吗?
<?php
session_start();
error_reporting(E_ALL);
if (array_key_exists("submit", $_POST)) {
$link = mysqli_connect("localhost", "eits_Admin", "WebSpinner1", "EITS_Sandbox");
if (!$link) {
die("Database connection error");
}
$error = '';
if (!$_POST['email']) {
$error .= "<br/>An email address is required";
}
if (!$_POST['password']) {
$error .= "<br/>A password is required";
}
if ($error != "") {
$error = "There were errors in your form - ".$error;
} else {
$query = "select id from secretdiary
where email = '".mysqli_real_escape_string($link, $_POST['email'])
."' limit 1";
// echo $query;
$result = mysqli_query($link, $query);
if (mysqli_num_rows($result) > 0) {
$error = "That email address is not available.";
} else {
$query = "insert into secretdiary
(email,password)
values ('" . mysqli_real_escape_string($link, $_POST['email'])
. "', '"
. mysqli_real_escape_string($link, $_POST['password']) . "')";
if (!mysqli_query($link, $query)) {
$error = "Could not sign you up at this time. Please try again later.";
} else {
$encPass = md5(md5(mysqli_insert_id($link)) . $_POST['password']);
$query = "update secretdiary
set password = '" . $encPass
. "' where id = " . mysqli_insert_id($link) . " limit 1";
echo $query;
$result = mysqli_query($link,$query);
echo "Sign up successful.";
}
}
}
}
?>
<div id="error"><? echo $error; ?></div>
<form method="post">
<input type="email" name="email" placeholder= "Your Email">
<input type="password" name="password" placeholder="Password">
<input type="checkbox" name="stayLoggedIn" value=1>
<input type="submit" name="submit" value="Sign Up!">
</form>
对于一个相对简单的过程,您有很多代码行。就个人而言,您的表单错误处理,例如它是否为空(在这种情况下)可以通过在每个 HTML 表单输入元素的末尾添加 required
来补救(这就是我要做的)
其次,md5 对散列密码不安全(你散列密码而不是加密它)
第三,这是一种使用 Bcrypt 从表单中散列密码的方法,这比使用 md5 散列法要好得多。因此,在 like counting the usernames and if row > 0 die('username exists)
使用 PDO
检查用户登录时只需使用 password_verify()
函数即可
整洁的代码可以帮助 SO 上的人了解您的问题所在,并且通常更易于阅读。我知道您可能只是在寻找“完成工作”的东西,但它可以在调试时帮助您,在您寻求帮助时帮助我们。
我将为您提供一种比您的方法更安全的方法。
index.php
<form method="post" id="regform" action="register.php">
<input type="text" name="username" placeholder="Enter your email Address"required/>
<input type="password" name="password" placeholder="Enter your password" required/>
<input type="submit" class="indexbttn" id="indexbttn" name="enter"value="enter"/>
</form>
connect.php
<?php
$servername = "localhost";
$dbusername = "root";
$dbpassword = "root";
$dbname = "fyp";
try{
$pdo = new PDO("mysql:host=$servername;dbname=$dbname",$dbusername, $dbpassword);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e)
{
print "Error! Unable to connect: " . $e->getMessage() . "<br/>";
die();
}
?>
register.php
<?php
session_start();
require_once ('connect.php');
error_reporting(E_ALL);
ini_set('display_errors', 1);
if(isset($_POST['enter'])){
$username = !empty($_POST['username']) ? trim($_POST['username']) : null;
$pass = !empty($_POST['password']) ? trim($_POST['password']) : null;
$check (!filter_var($_POST['username'], FILTER_VALIDATE_EMAIL));
$cnt = "SELECT COUNT(username) AS num FROM users WHERE username = :username";
$stmt = $pdo->prepare($cnt);
$stmt->bindValue(':username', $username);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
if($row['num'] > 0){
die('That username already exists!');
}
$passHash = password_hash($pass, PASSWORD_BCRYPT, array("cost" => 12));
$insrt = "INSERT INTO users (username, password) VALUES (:username, :password)";
$stmt = $pdo->prepare($insrt);
$stmt->bindValue(':username', $username);
$stmt->bindValue(':password', $passHash);
$result = $stmt->execute();
if($result){
header( "refresh:5;url=index.php" );
echo 'You will be redirected in 5 seconds. If not, click <a href="index.php">here</a>.';
}
}
?>
login.php
<?php
session_start();
require("connect.php");
if(isset($_POST['enter'])){
$username = !empty($_POST['username']) ? trim($_POST['username']) : null;
$pass = !empty($_POST['password']) ? trim($_POST['password']) : null;
$rtrv = "SELECT username, password, userid FROM users WHERE username = :username";
$stmt = $pdo->prepare($rtrv);
//Bind value.
$stmt->bindValue(':username', $username);
//Execute.
$stmt->execute();
//Fetch row.
$user = $stmt->fetch(PDO::FETCH_ASSOC);
//If $row is FALSE.
if($user === false){
//Could not find a user with that username!
die('Incorrect username');
}
else{
$validPassword = password_verify($pass, $user['password']);
if($validPassword){
$_SESSION['user_id'] = $user['username'];
$_SESSION['logged_in'] = time();
header( "Location: /protected.php" );
die();
} else{
die('Wrong password!');
}
}
}
?>