具有相同键值的多个数组合并成一个数组

Multiple array with same key value merge into an array

我遇到了多数组计算的问题。我正在使用数据库mysql,操作语言是PHP。当我从数据库中获取结果时,结果显示具有固定键和值的多个数组。当一个数组键代码值与单独的数组键代码值相同时,此数组将合并为一个包含总数量和价格的数组。这是从数据库中获取结果。

['code'=>'aaa','name'=>'a','qty'=>20,'price'=>12.00],
['code'=>'bbb','name'=>'b','qty'=>20,'price'=>12.00],
['code'=>'ccc','name'=>'c','qty'=>20,'price'=>12.00],
['code'=>'aaa','name'=>'a','qty'=>20,'price'=>12.00],
['code'=>'ddd','name'=>'d','qty'=>20,'price'=>12.00],
['code'=>'ccc','name'=>'c','qty'=>5,'price'=>8.00],
['code'=>'bbb','name'=>'b','qty'=>15,'price'=>10.00],
['code'=>'ggg','name'=>'g','qty'=>20,'price'=>12.00],

并且我想将此结果自定义为这种格式。

['code'=>'aaa','name'=>'a','qty'=>40,'price'=>24.00],
['code'=>'bbb','name'=>'b','qty'=>35,'price'=>22.00],
['code'=>'ccc','name'=>'c','qty'=>25,'price'=>20.00],
['code'=>'ddd','name'=>'d','qty'=>20,'price'=>12.00],
['code'=>'ggg','name'=>'g','qty'=>20,'price'=>12.00],

请帮我解决这个问题。我尝试了很多但没有得到任何解决方案。

可以通过一维数组实现...

$newArray = array();   //create new array..

foreach($array as $item) {
    if(isset($newArray[$item['code']])) { //if already exist then sum of qty and price...
        $newArray[$item['code']]['qty'] += $newArray[$item['code']]['qty'];
        $newArray[$item['code']]['price'] += $newArray[$item['code']]['price'];
    }else {   //if first time then add array into them...
        $newArray[$item['code']] = $item;
    }
}

通过使用查询你可以这样做

SELECT code, name, SUM(qty), SUM(price) 
from tableName 
group by code
SELECT code, name, SUM(qty), price 
from your_table_name 
group by name

在使用 mysql 获取结果时使用分组依据。希望这会有所帮助。

试试这个

    <?php 

error_reporting(0);
$array=array(['code'=>'aaa','name'=>'a','qty'=>20,'price'=>12.00],
['code'=>'bbb','name'=>'b','qty'=>20,'price'=>12.00],
['code'=>'ccc','name'=>'c','qty'=>20,'price'=>12.00],
['code'=>'aaa','name'=>'a','qty'=>20,'price'=>12.00],
['code'=>'ddd','name'=>'d','qty'=>20,'price'=>12.00],
['code'=>'ccc','name'=>'c','qty'=>5,'price'=>8.00],
['code'=>'bbb','name'=>'b','qty'=>15,'price'=>10.00],
['code'=>'ggg','name'=>'g','qty'=>20,'price'=>12.00]);


foreach($array as $item) {
        $newArray[$item['code']]['code'] = $item['code'];
        $newArray[$item['code']]['name'] = $item['name'];
        $newArray[$item['code']]['qty'] += $item['qty'];
        $newArray[$item['code']]['price'] +=$item['price'];
}
$newArray=array_values($newArray);

print_r($newArray);

?>

您可以使用array_reduce给您想要的结果。匿名回调检查结果数组中是否存在当前值的代码,如果存在,则对当前数量和价格求和。如果不是,则当前值被推入结果数组。该代码使用原始数组中的第一个值初始化结果,这样我们就不必担心未定义的索引:

$newdata = array_reduce(array_slice($data, 1),
    function ($c, $v) { 
        if (($k = array_search($v['code'], array_column($c, 'code'))) !== false) {
            $c[$k]['qty'] += $v['qty'];
            $c[$k]['price'] += $v['price'];
        }
        else {
            $c[] = $v;
        }
        return $c;
    }, array($data[0]));
print_r($newdata);

输出:

Array (
    [0] => Array ( [code] => aaa [name] => a [qty] => 40 [price] => 24 )
    [1] => Array ( [code] => bbb [name] => b [qty] => 35 [price] => 22 )
    [2] => Array ( [code] => ccc [name] => c [qty] => 25 [price] => 20 )
    [3] => Array ( [code] => ddd [name] => d [qty] => 20 [price] => 12 )
    [4] => Array ( [code] => ggg [name] => g [qty] => 20 [price] => 12 ) 
)

Demo on 3v4l.org