如何在jtable java中排序后根据搜索到的价格显示dishName?
How can I display dishName according to the searched price after sorting in jtable java?
private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) {
String dishName = "";
ArrayList<Integer> st = new ArrayList<Integer>();
int rowCount = table.getRowCount();
int fPrice;
int rowIndex = 0;
int colIndex = 4;
boolean emptyFlag = false;
do {
String price = (String) table.getValueAt(rowIndex, 4);
fPrice = Integer.parseInt(price);
if (price != null && price.length() != 0) {
st.add(fPrice);
rowIndex++;
} else {
emptyFlag = true;
}
} while (rowIndex < rowCount && !emptyFlag);
Collections.sort(st);
int key = Integer.parseInt(searchPrice.getText());
int low = 0;
int high = st.size() - 1;
int searchResult = MenuInfo.priceSearch(st, low, high, key);
if(searchResult==-1){
JOptionPane.showMessageDialog(this, "Could not find the dish of your price!");}
else{
dishName = (String) table.getValueAt(searchResult,1);
JOptionPane.showMessageDialog(this, "The price you have searched can afford " + dishName);
}
} //ends here
以上代码是我在程序中试过的代码。但只有事先对数据进行排序,才能显示对应的dishName。如果我添加价格较低的菜,那么它会显示第一行的菜名。请理解我的请求:)
Here is the image of my jtable
我写了一些可能有用的代码。看起来你用的是Swing,所以我用的是Swing。我的代码会找到相应的值,但不会对行进行排序。我会分享它,但如果您真的需要对它进行排序,请告诉我。
public static void main(String[] args) {
String[] headers = {"Name","Number"};
String[][] rowData = {{"foo","500"},{"bar","700"}};
JFrame frame = new JFrame();
JPanel panel = new JPanel();
//frame.add(panel);
//A table is controlled by its model, so we need a variable to access the model
DefaultTableModel model = new DefaultTableModel(rowData,headers);
JTable table = new JTable(model);
JScrollPane scroll = new JScrollPane(table);
//To allow sorting, we us a TableRowSorter object
TableRowSorter<TableModel> sorter = new TableRowSorter<>(table.getModel());
table.setRowSorter(sorter);
//We have to set the 2nd column to be sortable
ArrayList<RowSorter.SortKey> sortKeys = new ArrayList<>();
//sorting on 2nd column (with index of 1), which is Number
sortKeys.add(new RowSorter.SortKey(1, SortOrder.ASCENDING));
sorter.setSortKeys(sortKeys);
sorter.sort();
//add new value, then sort
Object[] newRow = {"baz", "600"};
model.addRow(newRow);
sorter.sort();
panel.add(scroll);
frame.add(panel);
frame.setSize(800, 400);
//show is deprecrated.. I shouldn't be using it!
frame.show();
int minIndex = findMin(table, 1);
//use the row index of the min item in column 1 to get the corresponding value in column 0
System.out.println("Minimum String: " + table.getValueAt(minIndex, 0));
}
//find min value in the column with index tableColumnIndex and return the row index of that item
public static int findMin(JTable table, int tableColumnIndex) {
int minIndex = 0;
String min = table.getValueAt(0, tableColumnIndex).toString();
for (int i = 1; i < table.getRowCount(); i++) {
if (table.getValueAt(i, tableColumnIndex).toString().compareTo(min) < 0) {
min = table.getValueAt(i, tableColumnIndex).toString();
minIndex = i;
}
}
return minIndex;
}
private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) {
String dishName = "";
ArrayList<Integer> st = new ArrayList<Integer>();
int rowCount = table.getRowCount();
int fPrice;
int rowIndex = 0;
int colIndex = 4;
boolean emptyFlag = false;
do {
String price = (String) table.getValueAt(rowIndex, 4);
fPrice = Integer.parseInt(price);
if (price != null && price.length() != 0) {
st.add(fPrice);
rowIndex++;
} else {
emptyFlag = true;
}
} while (rowIndex < rowCount && !emptyFlag);
Collections.sort(st);
int key = Integer.parseInt(searchPrice.getText());
int low = 0;
int high = st.size() - 1;
int searchResult = MenuInfo.priceSearch(st, low, high, key);
if(searchResult==-1){
JOptionPane.showMessageDialog(this, "Could not find the dish of your price!");}
else{
dishName = (String) table.getValueAt(searchResult,1);
JOptionPane.showMessageDialog(this, "The price you have searched can afford " + dishName);
}
} //ends here
以上代码是我在程序中试过的代码。但只有事先对数据进行排序,才能显示对应的dishName。如果我添加价格较低的菜,那么它会显示第一行的菜名。请理解我的请求:)
Here is the image of my jtable
我写了一些可能有用的代码。看起来你用的是Swing,所以我用的是Swing。我的代码会找到相应的值,但不会对行进行排序。我会分享它,但如果您真的需要对它进行排序,请告诉我。
public static void main(String[] args) {
String[] headers = {"Name","Number"};
String[][] rowData = {{"foo","500"},{"bar","700"}};
JFrame frame = new JFrame();
JPanel panel = new JPanel();
//frame.add(panel);
//A table is controlled by its model, so we need a variable to access the model
DefaultTableModel model = new DefaultTableModel(rowData,headers);
JTable table = new JTable(model);
JScrollPane scroll = new JScrollPane(table);
//To allow sorting, we us a TableRowSorter object
TableRowSorter<TableModel> sorter = new TableRowSorter<>(table.getModel());
table.setRowSorter(sorter);
//We have to set the 2nd column to be sortable
ArrayList<RowSorter.SortKey> sortKeys = new ArrayList<>();
//sorting on 2nd column (with index of 1), which is Number
sortKeys.add(new RowSorter.SortKey(1, SortOrder.ASCENDING));
sorter.setSortKeys(sortKeys);
sorter.sort();
//add new value, then sort
Object[] newRow = {"baz", "600"};
model.addRow(newRow);
sorter.sort();
panel.add(scroll);
frame.add(panel);
frame.setSize(800, 400);
//show is deprecrated.. I shouldn't be using it!
frame.show();
int minIndex = findMin(table, 1);
//use the row index of the min item in column 1 to get the corresponding value in column 0
System.out.println("Minimum String: " + table.getValueAt(minIndex, 0));
}
//find min value in the column with index tableColumnIndex and return the row index of that item
public static int findMin(JTable table, int tableColumnIndex) {
int minIndex = 0;
String min = table.getValueAt(0, tableColumnIndex).toString();
for (int i = 1; i < table.getRowCount(); i++) {
if (table.getValueAt(i, tableColumnIndex).toString().compareTo(min) < 0) {
min = table.getValueAt(i, tableColumnIndex).toString();
minIndex = i;
}
}
return minIndex;
}