allocated/reallocted 内存泄漏，“1 个块中的 5 个字节肯定丢失”

Question

我在检查我的程序是否存在内存泄漏时遇到 valgrind 错误。当 allocating/reallocating 内存时，错误发生在我的 cutString 函数的某处，但我不确定我做错了什么。

我的内存分配不正确吗？

这是 valgrind 的输出：

$ valgrind --leak-check=full --track-origins=yes ./cutstring
==7017== Memcheck, a memory error detector
==7017== Copyright (C) 2002-2017, and GNU GPL'd, by Julian Seward et al.           
==7017== Using Valgrind-3.14.0 and LibVEX; rerun with -h for copyright info                                     
==7017== Command: ./cutstring
==7017==
Hell
==7017==
==7017== HEAP SUMMARY:
==7017==     in use at exit: 5 bytes in 1 blocks
==7017==   total heap usage: 3 allocs, 2 frees, 1,042 bytes allocated                                           
==7017==
==7017== 5 bytes in 1 blocks are definitely lost in loss record 1 of 1                          
==7017==    at 0x4839D7B: realloc (vg_replace_malloc.c:826)
==7017==    by 0x109205: cutString (in cutstring)
==7017==    by 0x109228: main (in cutstring)
==7017==
==7017== LEAK SUMMARY:
==7017==    definitely lost: 5 bytes in 1 blocks
==7017==    indirectly lost: 0 bytes in 0 blocks
==7017==      possibly lost: 0 bytes in 0 blocks
==7017==    still reachable: 0 bytes in 0 blocks
==7017==         suppressed: 0 bytes in 0 blocks
==7017==
==7017== For counts of detected and suppressed errors, rerun with: -v
==7017== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 0 from 0)

这是我的代码：

#include <string.h>
#include <stdio.h>
#include <stdlib.h>

char *cutString(char *str, char del)
{ 
  char *new_string = (char*) malloc(strlen(str) * sizeof(char) + 1);

  int i = 0;
  while (str[i] != del)
  {
    new_string[i] = str[i];
    i++;
  }

  new_string[i] = '[=12=]';

  new_string = (char*) realloc(new_string, strlen(new_string) + 1);

  return new_string;
  free(new_string);
}

int main()
{
  printf("%s\n", cutString("Hello World!", 'o'));
  return 0;
}

我猜是我错误地使用了 realloc，但我不明白为什么。
一些帮助将不胜感激，谢谢！

Answer 1

cutString 必须分配内存并 return 它。当然（而且幸运的是）所有 after 一个无条件 return 的语句都没有达到。

  return new_string;
  free(new_string);   // never executed
}

幸运的是！因为否则你会 return 未分配的内存：未定义的行为。

这里的问题是您将 returned 值传递给 printf，但在该调用之后，指针丢失了。您必须存储它才能释放它，但是 只有在打印它后才能释放它。

int main()
{
  char *s = cutString("Hello World!", 'o'));
  printf("%s\n", s);
  free(s);
  return 0;
}

在 C 中，不可能在不造成内存泄漏的情况下流水线分配内存给 printf 的函数。其他语言有垃圾收集器或对象析构函数，但 C 没有。

allocated/reallocted 内存泄漏，“1 个块中的 5 个字节肯定丢失”

Memory leak at allocated/reallocted memory, "5 bytes in 1 blocks are definitely lost"

c

valgrind

memory-leaks