使用内部联接从第 3 table 行仅获取 1 行

Question

所以我要获取 3 个表：

问题、答案和成员。

这工作得很好，但问题是，我只想得到每个问题的第一行 answers。因此，如果一个问题有 50 个答案，我只想展示其中一个的片段。我查看了子查询和左连接，但它似乎不起作用。我该怎么做？

$queryGQ = "SELECT 
    questions.q_id,
    questions.question,
    questions.description,
    questions.link,
    questions.m_id AS qMID,
    questions.timestamp,
    questions.linktitle,
    questions.answers,
    questions.upvotes,
    answers.a_id,
    answers.q_id AS qQID,
    answers.answer,
    members.m_id AS mMID,
    members.navn,
    members.avidaname
        FROM
    questions
        INNER JOIN
    answers ON answers.q_id = questions.q_id
        INNER JOIN
    members ON questions.m_id = members.m_id
        WHERE public = '1'
        ORDER BY questions.timestamp DESC LIMIT $TheLimit";

    if ($stmtGQ = $con->prepare($queryGQ)) {

        /* execute statement */
        $stmtGQ->execute();

        /* bind result variables */
        $stmtGQ->bind_result($q_id, $question, $description, $link, $qMID, $timestamp, $linktitle, $answers, $upvotes, $aAID, $qQID, $answer, $mMID, $navn, $avidaname);

        /* fetch values */
        while ($stmtGQ->fetch()) {
            //MAGIC HAPPENS
        }
    }

Answer 1

如果您想保留获得最多赞成票的答案，那么您可以将另一个连接添加到子查询，该子查询会为每个问题找到最受欢迎的答案。然后，使用它来过滤您的结果集，使每个问题只有一个答案。

SELECT 
    q.q_id,
    q.question,
    q.description,
    q.link,
    q.m_id AS qMID,
    q.timestamp,
    q.linktitle,
    q.answers,
    q.upvotes,
    a.a_id,
    a.q_id AS qQID,
    a.answer,
    m.m_id AS mMID,
    m.navn,
    m.avidaname
FROM questions q
INNER JOIN answers a
    ON a.q_id = q.q_id
INNER JOIN
(
    SELECT q_id, MAX(upvotes) AS max_upvotes
    FROM answers
    GROUP BY q_id
) a2
    ON a.q_id = a2.q_id AND a.upvotes = a2.max_upvotes
INNER JOIN members m
    ON q.m_id = m.m_id
WHERE
    public = '1'
ORDER BY
    q.timestamp DESC;

使用内部联接从第 3 table 行仅获取 1 行

Get only 1 row from 3rd table with inner join

php

mysqli

prepared-statement