再试一次 Do-While 循环

Question

这是一个非常简单的程序。计算机和用户在 0-3 之间选择一个数字。如果用户没有猜到与计算机相同的数字，我希望程序循环返回。

    String input; // input is a string variable
    int cpucrazy;
    int convertstring;

// 第一步 //

    input = JOptionPane.showInputDialog("Guess a number between 0-3");
    convertstring = Integer.parseInt(input);

// 随机部分 //

    Random ran = new Random ();
    cpucrazy = ran.nextInt(3);

//计算！

if (cpucrazy < convertstring) {
     JOptionPane.showInputDialog(null, "Your guess is too high. Guess again?"); }


else if (cpucrazy > convertstring) {
     JOptionPane.showInputDialog(null, "Your guess is too low. Guess again?"); }


else JOptionPane.showMessageDialog(null, "Correct!!");

Answer 1

if (cpucrazy < convertstring) {
 JOptionPane.showInputDialog(null, "Your guess is too high. Guess again?"); }


else if (cpucrazy > convertstring) {
     JOptionPane.showInputDialog(null, "Your guess is too low. Guess again?"); }


else JOptionPane.showMessageDialog(null, "Correct!!");

您需要在上述代码周围放置一个 while 循环（或某种类型的循环结构）并在以下情况下退出该结构：cpucrazy == convertstring 或在 cpucrazy != convertstring[=14 时留在循环结构中=]

循环可能类似于以下伪代码：

b = random();

do
{
     input a;
     if( a != b )
     {
         if(a < b )
         {
              print "Too low";
         }
         else
         {
              print "Too high";
         }
     }
} while( a != b );

print "You got it correct"

再试一次 Do-While 循环

Try Again Do-While Loop

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