Pandas 包含不匹配的完整字符串

Question

我在使用这个 df 的 .contains 函数时遇到了问题。为什么它与我的字符串不匹配？显然 df 有字符串。它单独匹配 "Chief"。

import pandas as pd
link = 'https://www.sec.gov/Archives/edgar/data/1448056/000119312518215760/d619223ddef14a.htm'
ceo = 'Chief Executive Officer'
df_list = pd.read_html(link)
df = df_list[62]
df = df.fillna('')

for column in df:
    if column == 4:
        print ('try #1', df[column].str.contains(ceo, case=True, regex=True))
        print ('try #2', df[column].str.contains(ceo, case=True, regex=False))
        print ('try #3', df[column].str.contains(ceo, regex=False))
        print ('try #4', df[column].str.contains(ceo, regex=True))
        print ('try #5', df[column].str.contains(pat=ceo, regex=False))
        print ('try #6', df[column].str.contains(pat=ceo, case=True, regex=True))

Answer 1

问题出在编码上，你看看就知道了：

df[4].iloc[2]

因为它打印：

'Founder,\xa0Chief\xa0Executive\xa0Officer,\xa0and\xa0Director'

要修复它，请使用 unidecode：

import unidecode

for column in df.columns:
    if column == 4:
        print ('try #1', df[column].apply(lambda x: 
        unidecode.unidecode(x)).str.contains(ceo, case=True, regex=True))
        print ('try #2', df[column].apply(lambda x: 
        unidecode.unidecode(x)).str.contains(ceo, case=True, regex=False))
        print ('try #3', df[column].apply(lambda x: 
        unidecode.unidecode(x)).str.contains(ceo, regex=False))
        print ('try #4', df[column].apply(lambda x: 
        unidecode.unidecode(x)).str.contains(ceo, regex=True))
        print ('try #5', df[column].apply(lambda x: 
        unidecode.unidecode(x)).str.contains(pat=ceo, regex=False))
        print ('try #6', df[column].apply(lambda x: 
        unidecode.unidecode(x)).str.contains(pat=ceo, case=True, regex=True))

Pandas 包含不匹配的完整字符串

Pandas contains not matching full string

contains

pandas