如何通过laravel中的join query查看路由

Question

我有这条路由通过通知模型：

Route::view('masaya', 'pages.notifications-table', [
    'data' => App\Notification::all()
]);

如何将此查询而不是模型传递给：

$inspect = DB::table('notifications')
    ->leftJoin('franchises', 'franchises.id', '=', 'notifications.franchise_id')
    ->leftJoin('units', 'units.id', '=', 'notifications.unit_id')
    ->select('franchises.id as fid', 'franchises.case_number', 'franchises.authorize_units', 'franchises.deno', 'franchises.route_name', 'franchises.expiry_date', 'franchises.date_granted', 'units.id as uid', 'units.plate_number', 'units.motor_number', 'units.chassis_number', 'units.make', 'notifications.id', 'notifications.remarks', 'notifications.created_at', 'notifications.plate_picture')
    ->orderBy('units.updated_at', 'desc')
    ->paginate(20);

Answer 1

如果这是您经常使用的结果集，您可以在 App\Notification 模型中使用静态方法，例如：

public static function withFranchisesAndUnits()
{
    return \DB::table('notifications')
        ->leftJoin('franchises', 'franchises.id', '=', 'notifications.franchise_id')
        ->leftJoin('units', 'units.id', '=', 'notifications.unit_id')
        ->select('franchises.id as fid', 'franchises.case_number', 'franchises.authorize_units', 'franchises.deno', 'franchises.route_name', 'franchises.expiry_date', 'franchises.date_granted', 'units.id as uid', 'units.plate_number', 'units.motor_number', 'units.chassis_number', 'units.make', 'notifications.id', 'notifications.remarks', 'notifications.created_at', 'notifications.plate_picture')
        ->orderBy('units.updated_at', 'desc')
        ->paginate(20);
}

.. 就这样称呼它：

Route::view('masaya', 'pages.notifications-table', [
    'data' => App\Notification::withFranchisesAndUnits()
]);

如何通过laravel中的join query查看路由

How to pass join query in laravel to view route

jquery

query-builder

laravel

eloquent

laravel-5