合并对象数组而不覆盖
Merging an array of objects without overwriting
我目前正在使用一些 JSON,它必须以树状层次结构构建。层次结构的深度变化很大,因此未知。
就目前而言,我已经获得了一个对象数组。示例如下。
[
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "Level 1 item here",
"id": 360082134191
}
]
},
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "level2",
"collapsed": true,
"children": [
{
"name": "Level 2 item here",
"id": 360082134751
}
]
}
]
},
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "Another level 1 item",
"id": 360082262772
}
]
}
]
我想要实现的是将这些对象合并,而不覆盖或替换任何东西。下面列出的是我希望如何格式化数据的示例:
[
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "level2",
"collapsed": true,
"children": [
{
"name": "Level 2 item here",
"id": 360082134751
}
]
},
{
"name": "Level 1 item here",
"id": 360082134191
},
{
"name": "Another level 1 item",
"id": 360082262772
}
]
}
]
如何使用 JavaScript 实现此目的?没有库是首选,但可以使用 ES6。
编辑:
输出是一个数组很重要,因为没有子项的项目可以出现在根部。
我假设您在处理数据方面需要一些帮助。可能有多种方法可以实现这一点,这里是我会怎么做。
// data => supplied data
const result = data.reduce ((acc, item) => {
// if acc array already contains an object with same name,
// as current element [item], merfe the children
let existingItem;
// Using a for loop here to create a reference to the
// existing item, so it'd update this item when childrens
// will be merged.
for (let index = 0; index < acc.length; index ++) {
if (acc[index].name === item.name) {
existingItem = acc[index];
break;
}
}
// if existingItem exists, merge children of
// existing item and current item.
// else push it into the accumulator
if (existingItem) {
existingItem.children = existingItem.children.concat(item.children);
} else {
acc.push (item);
}
return acc;
}, []);
我假设您想根据级别 1 对象中的 name
属性 进行分组。你可以像这样做一个简单的 reduce
and Object.values
:
const input = [{"name":"level1","collapsed":true,"children":[{"name":"Level 1 item here","id":360082134191}]},{"name":"level1","collapsed":true,"children":[{"name":"level2","collapsed":true,"children":[{"name":"Level 2 item here","id":360082134751}]}]},{"name":"level1","collapsed":true,"children":[{"name":"Another level 1 item","id":360082262772}]}]
const merged = input.reduce((r,{name, collapsed, children}) =>{
r[name] = r[name] || {name, collapsed, children:[]};
r[name]["children"].push(...children)
return r;
}, {})
const final = Object.values(merged);
console.log(final)
你可以在一行中完成所有事情:
const input = [{"name":"level1","collapsed":true,"children":[{"name":"Level 1 item here","id":360082134191}]},{"name":"level1","collapsed":true,"children":[{"name":"level2","collapsed":true,"children":[{"name":"Level 2 item here","id":360082134751}]}]},{"name":"level1","collapsed":true,"children":[{"name":"Another level 1 item","id":360082262772}]}]
const output = Object.values(input.reduce((r,{name,collapsed,children}) => (
(r[name] = r[name] || {name,collapsed,children: []})["children"].push(...children), r), {}))
console.log(output)
我目前正在使用一些 JSON,它必须以树状层次结构构建。层次结构的深度变化很大,因此未知。
就目前而言,我已经获得了一个对象数组。示例如下。
[
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "Level 1 item here",
"id": 360082134191
}
]
},
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "level2",
"collapsed": true,
"children": [
{
"name": "Level 2 item here",
"id": 360082134751
}
]
}
]
},
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "Another level 1 item",
"id": 360082262772
}
]
}
]
我想要实现的是将这些对象合并,而不覆盖或替换任何东西。下面列出的是我希望如何格式化数据的示例:
[
{
"name": "level1",
"collapsed": true,
"children": [
{
"name": "level2",
"collapsed": true,
"children": [
{
"name": "Level 2 item here",
"id": 360082134751
}
]
},
{
"name": "Level 1 item here",
"id": 360082134191
},
{
"name": "Another level 1 item",
"id": 360082262772
}
]
}
]
如何使用 JavaScript 实现此目的?没有库是首选,但可以使用 ES6。
编辑: 输出是一个数组很重要,因为没有子项的项目可以出现在根部。
我假设您在处理数据方面需要一些帮助。可能有多种方法可以实现这一点,这里是我会怎么做。
// data => supplied data
const result = data.reduce ((acc, item) => {
// if acc array already contains an object with same name,
// as current element [item], merfe the children
let existingItem;
// Using a for loop here to create a reference to the
// existing item, so it'd update this item when childrens
// will be merged.
for (let index = 0; index < acc.length; index ++) {
if (acc[index].name === item.name) {
existingItem = acc[index];
break;
}
}
// if existingItem exists, merge children of
// existing item and current item.
// else push it into the accumulator
if (existingItem) {
existingItem.children = existingItem.children.concat(item.children);
} else {
acc.push (item);
}
return acc;
}, []);
我假设您想根据级别 1 对象中的 name
属性 进行分组。你可以像这样做一个简单的 reduce
and Object.values
:
const input = [{"name":"level1","collapsed":true,"children":[{"name":"Level 1 item here","id":360082134191}]},{"name":"level1","collapsed":true,"children":[{"name":"level2","collapsed":true,"children":[{"name":"Level 2 item here","id":360082134751}]}]},{"name":"level1","collapsed":true,"children":[{"name":"Another level 1 item","id":360082262772}]}]
const merged = input.reduce((r,{name, collapsed, children}) =>{
r[name] = r[name] || {name, collapsed, children:[]};
r[name]["children"].push(...children)
return r;
}, {})
const final = Object.values(merged);
console.log(final)
你可以在一行中完成所有事情:
const input = [{"name":"level1","collapsed":true,"children":[{"name":"Level 1 item here","id":360082134191}]},{"name":"level1","collapsed":true,"children":[{"name":"level2","collapsed":true,"children":[{"name":"Level 2 item here","id":360082134751}]}]},{"name":"level1","collapsed":true,"children":[{"name":"Another level 1 item","id":360082262772}]}]
const output = Object.values(input.reduce((r,{name,collapsed,children}) => (
(r[name] = r[name] || {name,collapsed,children: []})["children"].push(...children), r), {}))
console.log(output)