算术右移在 Verilog HDL 中不起作用
Arithmetic right shift not working in Verilog HDL
我正在构建一个移位单元,它能够根据提供给它的控制信号进行算术和逻辑右移以及逻辑左移。但是,算术右移运算符输出生成类似于逻辑右移运算符的输出,即不会发生符号扩展。
主要代码
`timescale 1ns / 1ps
module shift_unit(
input [15:0] a,
input [3:0] b,
input clk,
input isLSL,
input isLSR,
input isASR,
output reg [15:0] result
);
wire [15:0] LSL_result, LSR_result, ASR_result;
LSL lsl(a, b, clk, isLSL, LSL_result);
LSR lsr(a, b, clk, isLSR, LSR_result);
ASR asr(a, b, clk, isASR, ASR_result);
always@(posedge clk) begin
case({isLSL, isLSR, isASR})
3'b001: result <= ASR_result;
3'b010: result <= LSR_result;
3'b100: result <= LSL_result;
endcase
end
endmodule
LSL代码:
`timescale 1ns / 1ps
module LSL(
input [15:0] a,
input [3:0] b,
input clk,
input isLSL,
output [15:0] out
);
reg [15:0] result;
always@(posedge clk) begin
if(isLSL) result = a << b;
end
assign out = result;
endmodule
LSR代码:
`timescale 1ns / 1ps
module LSR(
input [15:0] a,
input [3:0] b,
input clk,
input isLSR,
output [15:0] out
);
reg [15:0] result;
always@(posedge clk) begin
if(isLSR) result = a >> b;
end
assign out = result;
endmodule
ASR 代码:
`timescale 1ns / 1ps
module ASR(
input [15:0] a,
input [3:0] b,
input clk,
input isASR,
output [15:0] out
);
reg [15:0] result;
always@(posedge clk) begin
if(isASR) result = a >>> b;
end
assign out = result;
endmodule
最后,测试平台:
`timescale 1ns / 1ps
module shift_unit_test;
reg [15:0] a;
reg [3:0] b;
reg clk;
reg isLSL;
reg isLSR;
reg isASR;
wire [15:0] result;
shift_unit uut (
.a(a),
.b(b),
.clk(clk),
.isLSL(isLSL),
.isLSR(isLSR),
.isASR(isASR),
.result(result)
);
always #5 clk = ~clk;
initial begin
clk = 1'b0;
a = 16'b1100101011001010;
b = 4;
{isLSL, isLSR, isASR} = 3'b100; #100;
{isLSL, isLSR, isASR} = 3'b010; #100;
{isLSL, isLSR, isASR} = 3'b001; #100;
end
endmodule
以上代码已使用 Xilinx ISE 14.7 建模。
任何帮助将不胜感激。
您需要使用 signed
信号才能获得符号扩展。
module ASR(
input wire signed [15:0] a,
input [3:0] b,
input clk,
input isASR,
output reg signed [15:0] out
);
always@(posedge clk) begin
if(isASR) out = a >>> b;
end
endmodule
我正在构建一个移位单元,它能够根据提供给它的控制信号进行算术和逻辑右移以及逻辑左移。但是,算术右移运算符输出生成类似于逻辑右移运算符的输出,即不会发生符号扩展。
主要代码
`timescale 1ns / 1ps
module shift_unit(
input [15:0] a,
input [3:0] b,
input clk,
input isLSL,
input isLSR,
input isASR,
output reg [15:0] result
);
wire [15:0] LSL_result, LSR_result, ASR_result;
LSL lsl(a, b, clk, isLSL, LSL_result);
LSR lsr(a, b, clk, isLSR, LSR_result);
ASR asr(a, b, clk, isASR, ASR_result);
always@(posedge clk) begin
case({isLSL, isLSR, isASR})
3'b001: result <= ASR_result;
3'b010: result <= LSR_result;
3'b100: result <= LSL_result;
endcase
end
endmodule
LSL代码:
`timescale 1ns / 1ps
module LSL(
input [15:0] a,
input [3:0] b,
input clk,
input isLSL,
output [15:0] out
);
reg [15:0] result;
always@(posedge clk) begin
if(isLSL) result = a << b;
end
assign out = result;
endmodule
LSR代码:
`timescale 1ns / 1ps
module LSR(
input [15:0] a,
input [3:0] b,
input clk,
input isLSR,
output [15:0] out
);
reg [15:0] result;
always@(posedge clk) begin
if(isLSR) result = a >> b;
end
assign out = result;
endmodule
ASR 代码:
`timescale 1ns / 1ps
module ASR(
input [15:0] a,
input [3:0] b,
input clk,
input isASR,
output [15:0] out
);
reg [15:0] result;
always@(posedge clk) begin
if(isASR) result = a >>> b;
end
assign out = result;
endmodule
最后,测试平台:
`timescale 1ns / 1ps
module shift_unit_test;
reg [15:0] a;
reg [3:0] b;
reg clk;
reg isLSL;
reg isLSR;
reg isASR;
wire [15:0] result;
shift_unit uut (
.a(a),
.b(b),
.clk(clk),
.isLSL(isLSL),
.isLSR(isLSR),
.isASR(isASR),
.result(result)
);
always #5 clk = ~clk;
initial begin
clk = 1'b0;
a = 16'b1100101011001010;
b = 4;
{isLSL, isLSR, isASR} = 3'b100; #100;
{isLSL, isLSR, isASR} = 3'b010; #100;
{isLSL, isLSR, isASR} = 3'b001; #100;
end
endmodule
以上代码已使用 Xilinx ISE 14.7 建模。 任何帮助将不胜感激。
您需要使用 signed
信号才能获得符号扩展。
module ASR(
input wire signed [15:0] a,
input [3:0] b,
input clk,
input isASR,
output reg signed [15:0] out
);
always@(posedge clk) begin
if(isASR) out = a >>> b;
end
endmodule