无法在我的剪刀石头布主语句中执行调用函数

Question

在任何人将此问题标记为与其他任何人有关此类程序的重复问题之前，请知道我搜索并阅读了有关此主题的已回答问题，但找不到适合我需要的任何内容。

在我的剪刀石头布程序中，我被要求判断计算机或玩家是否获胜，或者他们是否平手。我们应该将计算机获胜存储为 -1，玩家获胜存储为 1，平局存储为 0。我认为我正确地编写了这个函数并在我的主要函数中正确调用了它，但是，当我运行我的代码时它会跳过就在我的运行Game 函数上方，而是跳到一个无限循环，要求玩家输入他们的选择。我不知道为什么会这样。我应该注意到，在我的主要功能中，我们应该保留一个计数器来查看计算机和玩家有多少次获胜，以及他们打平了多少次。我也很难让它执行。

import random

# Function: Display Menu
# Input: none
# Output: none
# displays the game rules to the user
def displayMenu():
    print("Welcome! Let's play rock, paper, scissors.")
    print("The rules of the game are:")
    print("\tRock smashes scissors")
    print("\tScissors cut paper")
    print("\tPaper covers rock")
    print("\tIf both the choices are the same, it's a tie")

# Function: Get Computer Choice
# Input: none
# Output: integer that is randomly chosen, a number between 0 to 2
def getComputerChoice():
    computerChoice = random.randrange(0,3)
    return computerChoice

# Function: Get Player Choice
# Input: none
# Output: integer that represents the choice
# Asks the user for their choice: 0 for rock, 1 for paper, or 2 for scissors
def getPlayerChoice():
    playerChoice = int(input("Please choose (0) for rock, (1) for paper or (2) for scissors"))
    return playerChoice

# Function: Play Round
# Input: two integers--one representing the computer's choice and the other representing the player's choice
# Output: integer (-1 if computer wins, 1 if player wins, 0 if there is a tie)
# This method contains the game logic so it stimulates the game and determines a winner
def playRound(computerChoice, playerChoice):
    if playerChoice == 0 and computerChoice == 2:
        return 1
    elif computerChoice == 0 and playerChoice == 2:
        return -1
    elif playerChoice == 2 and computerChoice == 1:
        return 1
    elif computerChoice == 2 and playerChoice == 1:
        return -1
    elif playerChoice == 1 and computerChoice == 0:
        return 1
    elif computerChoice == 1 and playerChoice == 0:
        return 1
    else:
        return 0

# Function: Continue Game
# Input: none
# Output: boolean
# Ask the user is they want to continue (Y/N), and then return True or False accordingly
def continueGame():
    playAgain = input("Do you want to continue playing? Enter (y) for yes or (n) for no.")
    if playAgain.lower() == "y":
        return True
    elif playAgain.lower() == "n":
        return False

# Function: main
# Input: none
# Output: none
def main():
    playerCounter = 0
    computerCounter = 0
    tieCounter = 0

    displayMenu()
    p_choice = getPlayerChoice()
    if p_choice == 0:
        choicePlayer = "rock"
    elif p_choice == 1:
        choicePlayer = "paper"
    elif p_choice == 2:
        choicePlayer = "scissors"
    getComputerChoice()
    c_choice = getComputerChoice()
    if c_choice == 0:
        choiceComputer = "rock"
    elif c_choice == 1:
        choiceComputer = "paper"
    elif c_choice == 2:
        choiceComputer = "scissors"
    print("You chose", choicePlayer + ".")
    print("The computer chose", choiceComputer + ".")
    playRound(getComputerChoice(), getPlayerChoice())
    while playRound(c_choice, p_choice) == -1:
        computerCounter += 1
    while playRound(getPlayerChoice(), getPlayerChoice()) == 1:
        playerCounter += 1
    while playRound(getPlayerChoice(), getPlayerChoice()) == 0:
        tieCounter += 1
    continueGame()
    while continueGame() == True:
        displayMenu()
        getPlayerChoice()
        getComputerChoice()
        playRound(getComputerChoice(), getPlayerChoice())
        continueGame()
    while continueGame() == False:
        print()
        print("You won", playerCounter, "game(s).")
        print("The computer won", computerCounter, "game(s).")
        print("You tied with the computer", tieCounter, "time(s).")
        print()
        print("Thanks for playing!")

# Call Main
main()

Answer 1

您没有 "runGame" 方法，我相信您指的是 playRound。在这种情况下，再次在这一行中：

 playRound(getComputerChoice(), getPlayerChoice())

您正在再次调用 getComputerChoice() 和 getPlayerChoice() 方法，这不是您想要的。因此，它再次要求您输入。你应该这样做：

playRound(c_choice, p_choice)

Answer 2

您的代码存在一些问题。首先，您在不需要时多次调用 getComputerChoice()、getPlayerChoice() 和 continueGame() 函数。其次，你有多个奇怪的 while 循环，它们并没有按照你的实际想法去做。

您可以通过以下方式修改您的函数以使程序正常运行。

def main():
    playerCounter = 0
    computerCounter = 0
    tieCounter = 0

    displayMenu()
    next_game = True

    while next_game:
        p_choice = getPlayerChoice()
        if p_choice == 0:
            choicePlayer = "rock"
        elif p_choice == 1:
            choicePlayer = "paper"
        elif p_choice == 2:
            choicePlayer = "scissors"
        c_choice = getComputerChoice()
        if c_choice == 0:
            choiceComputer = "rock"
        elif c_choice == 1:
            choiceComputer = "paper"
        elif c_choice == 2:
            choiceComputer = "scissors"
        print("You chose", choicePlayer + ".")
        print("The computer chose", choiceComputer + ".")

        result = playRound(p_choice, c_choice)
        if result == -1:
            computerCounter += 1
        elif result == 0:
            tieCounter += 1
        else:
            playerCounter += 1

        next_game = continueGame()

    print("You won", playerCounter, "game(s).")
    print("The computer won", computerCounter, "game(s).")
    print("You tied with the computer", tieCounter, "time(s).")
    print()
    print("Thanks for playing!")

无法在我的剪刀石头布主语句中执行调用函数

Inability to execute the call function within my main statement for rock, paper, scissors

python

main

class

function