将整数加在一起并得到错误的答案

Question

我正在编写一个赌场骰子游戏，要求用户输入赌注和骰子号码。骰子数的结果将从余额中扣除赌注或将赌注 * 6 添加到余额中。当用户猜错时，从余额中扣除正确的值。

余额为 490，下注 5 后赢了，新余额为 556045。这显然应该是 520。

为什么新余额会是 556045？

我的代码连同输出在下面

    import random

print("Welcome to the casino")
UserName = input("Please enter your name: ")
print("Thanks for playing " + UserName + "! We wish you the best of luck!")

balanceRemaining = 500
while balanceRemaining != 0:
    RandomNumber = random.randint(1, 6)
    Wager = input("Please enter a wager: ")
    UserNumber = input("Enter a number: ")
    print("Dice number was " + str(RandomNumber))
    if int(UserNumber) != RandomNumber:
        balanceRemaining = balanceRemaining - int(Wager)
        print("Your Balance is now: " + str(balanceRemaining))
    else:
        Winnings = int(Wager * 6)
        balanceRemaining = int(Winnings) + int(balanceRemaining)
        print("Your Balance is now: " + str(balanceRemaining))

输出

Please enter a wager: 5
Enter a number: 5
Dice number was 1
Your Balance is now: 495
Please enter a wager: 5
Enter a number: 5
Dice number was 6
Your Balance is now: 490
Please enter a wager: 5
Enter a number: 5
Dice number was 5
Your Balance is now: 556045

Answer 1

您需要先转换投注字符串然后乘以：

Winnings = int(Wager) * 6

Wager 是一个字符串，所以 '5' 并且允许乘以字符串，这会产生一个具有重复值的新字符串：

>>> '5' * 6
'555555'

然后转换该新字符串，产生比您预期的大得多的赢利。

最好尽早转换用户输入，这样就很难在代码的其他地方犯此类错误。这也有助于减少将输入转换为整数所需的位置数：

Wager = int(input("Please enter a wager: "))
UserNumber = int(input("Enter a number: "))

Answer 2

这真的很有趣。这里你输入一个字符串：

Wager = input("Please enter a wager: ")

而 Wager 在您的情况下是 字符串 "5"。然后，您将 string 乘以 6:

Winnings = int(Wager * 6)

与Winnings = int("5"* 6)相同，但是"5"* 6 == '555555'！然后，int 将其转换为整数，您得到的结果不正确。

您想将什么转换为整数：字符串 "5"* 6 还是字符串 "5"？你肯定是指：

Winnings = int(Wager) * 6

将整数加在一起并得到错误的答案

Adding int's together and getting the wrong anser

python

int

calculation