循环将一个列表的每个元素与第二个列表的四个元素相乘以获得新列表的函数

Question

我有两个列表，一个长度为 40，另一个长度为 10.I 想将 40 列表的前四个元素与第二个列表的第一个元素相乘，然后循环整个第一个列表40 得到一个新列表，这是这两个的乘积。关于如何解决这个问题有什么建议吗？

from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

v=[[a1/ b1 for a1 in a4] for a4, b1 in zip(grouper(active, 4), passive)]

active=[56.93977737426758,
 54.12062072753906,
 54.89398765563965,
 55.214101791381836,
 54.29464149475098,
 53.80845832824707,
 54.46353721618652,
 54.49761962890625,
 53.01671028137207,
 53.872962951660156,
 53.156455993652344,
 53.20746994018555,
 52.529762268066406,
 56.03120040893555,
 54.122426986694336,
 55.83853149414063,
 53.51207160949707,
 54.82537269592285,
 53.569284439086914,
 53.5296745300293,
 54.354637145996094,
 54.313310623168945,
 53.26720809936523,
 54.64541053771973,
 55.00912475585938,
 55.093666076660156,
 55.138763427734375,
 54.19987297058106,
 54.07197189331055,
 53.18226623535156,
 53.656246185302734,
 54.97188377380371,
 55.28757095336914,
 54.08882141113281,
 53.08153915405274,
 53.61944770812988,
 53.15986633300781,
 53.53702735900879,
 53.32623863220215,
 52.01462173461914]

passive= [54.46392059326172,
 52.37292861938477,
 51.95756149291992,
 53.40110778808594,
 54.46831512451172,
 56.04657173156738,
 57.74487495422363,
 53.75052452087402,
 56.246402740478516,
 55.15713691711426]

我当前的输出是 10.I 的列表想要 40.I 的列表想要将主动的前四个元素与被动的第一个元素相除......所以 on.In 最后我想要一个包含 40 个元素而不是 10 个元素的新列表。例如 [active1/passive1,active2/passive1,active3/passive1..active40/passive10]

[[1.0454586587604597,
  0.9936967470945319,
  1.0078963662125922,
  1.0137739110579735],
 [1.0366928664488493,
  1.0274097658218595,
  1.0399177333006342,
  1.040568497228071],
 [1.020384882546816,
  1.0368647296698332,
  1.0230744951511204,
  1.0240563338877238],
 [0.9836830066620091,
  1.0492516490722763,
  1.013507569945381,
  1.045643691807429],
 [0.9824440408551517,
  1.0065553261670555,
  0.9834944282126284,
  0.982767218109524],
 [0.9698119879004422,
  0.9690746274955083,
  0.9504097477092123,
  0.9750000553011796],
 [0.9526234977470646,
  0.954087546649548,
  0.9548685224696527,
  0.9386092361191739],
 [1.005980357871888,
  0.9894278559960512,
  0.9982460015709302,
  1.0227227411047006],
 [0.9829530113857514,
  0.9616405454531767,
  0.9437321600631335,
  0.9532955903958973],
 [0.9637894441999811,
  0.9706273811757119,
  0.9668057773255447,
  0.9430261366318299]]

Answer 1

例如

a = range(40)
b = range(10)

最简单的：

[x * b[i//4] for i, x in enumerate(a)]

更多功能：

# from https://docs.python.org/3/library/itertools.html#itertools-recipes
from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

[a1 * b1 for a4, b1 in zip(grouper(a, 4), b) for a1 in a4]

Answer 2

您可以在一行中使用纯 Python 来完成：

newList = [active[j] / passive[i] for i in range(len(passive)) for j in range(i*4,i*4+4)]
for elem in newList:
    print(elem)

这将打印：

1.0454586587604597
0.9936967470945319
1.0078963662125922
1.0137739110579735
1.0366928664488493
1.0274097658218595
1.0399177333006342
1.040568497228071
1.020384882546816
1.0368647296698332
1.0230744951511204
1.0240563338877238
0.9836830066620091
1.0492516490722763
1.013507569945381
1.045643691807429
0.9824440408551517
1.0065553261670555
0.9834944282126284
0.982767218109524
0.9698119879004422
0.9690746274955083
0.9504097477092123
0.9750000553011796
0.9526234977470646
0.954087546649548
0.9548685224696527
0.9386092361191739
1.005980357871888
0.9894278559960512
0.9982460015709302
1.0227227411047006
0.9829530113857514
0.9616405454531767
0.9437321600631335
0.9532955903958973
0.9637894441999811
0.9706273811757119
0.9668057773255447
0.9430261366318299

乘法也一样：

newList = [active[j] * passive[i] for i in range(len(passive)) for j in range(i*4,i*4+4)]

循环将一个列表的每个元素与第二个列表的四个元素相乘以获得新列表的函数

Function that multiplies each element of one list with four elements of second list in a loop to get a new list

python

list

multiplication