Bash 将命令输出与字符串进行比较

Question

输出是一样的，总是回显need to pull。如果我在 if 条件下删除 $text 周围的引号，它会抛出 too many arguments 错误。

var="$(git status -uno)" && 

text="On branch master Your branch is up-to-date with 'origin/master'. nothing to commit (use -u to show untracked files)"; 

echo  $var; 
echo  $text; 
if [ "$var" = "$text" ]; then
    echo "Up-to-date"
else
    echo "need to pull"
fi

Answer 1

最好这样做，=~ for bash regex :

#!/bin/bash

var="$(git status -uno)" 

if [[ $var =~ "nothing to commit" ]]; then
    echo "Up-to-date"
else
    echo "need to pull"
fi

或

#!/bin/bash

var="$(git status -uno)" 

if [[ $var == *nothing\ to\ commit* ]]; then
    echo "Up-to-date"
else
    echo "need to pull"
fi

Answer 2

警告： bash's regex require more ressources and won't work in other shell!

简约老款

此语法 POSIX 兼容，而非 bash！

if LANG=C git status -uno | grep -q up-to-date ; then
    echo "Nothing to do"
else
    echo "Need to upgrade"
fi

或测试变量（posix 也是）

来自 this answer to How to check if a string contains a substring in Bash，这是一个兼容的语法，在 any standard POSIX shell[=31 下工作=]:

#!/bin/sh stringContain() { [ -z "${2##**}" ] && { [ -z "" ] || [ -n "" ] ;} ; } var=$(git status -uno) if stringContain "up-to-date" "$var" ;then echo "Up-to-date" # Don't do anything else echo "need to pull" # Ask for upgrade, see: fi

Bash 将命令输出与字符串进行比较

Bash compare a command output to string

bash

git-bash

简约老款

或测试变量（posix 也是）