遍历 2 个对象数组和 return 单个对象数组的有效方法是什么？

Question

我想遍历 exerxises 数组，将每个 object.id 与 searchResult 的 object.id 和 return 不相等的 searchResult 对象在新数组中进行比较，不重复。

我遇到了问题，因为两个数组的长度不同

const exercises = [
 {
  id: 'pull-ups',
  title: 'Pull Ups',
  description: 'Back and biceps exercise...',
  muscles: 'back'
 },
 {
  id: 'deadlifts',
  title: 'Deadlifts',
  description: 'Back and leg exercise...',
  muscles: 'back'
 },
 {
  id: 'squats',
  title: 'Squats',
  description: 'Legs exercise...',
  muscles: 'legs'
 }
]

const searchResult = [
 {
  id: 'overhead-press',
  title: 'Overhead Press',
  description: 'Delts exercise...',
  muscles: 'shoulders'
 },
 {
  id: 'dips',
  title: 'Dips',
  description: 'Triceps exercise...',
  muscles: 'arms'
 },
 {
  id: 'barbell-curls',
  title: 'Barbell Curls',
  description: 'Biceps exercise...',
  muscles: 'arms'
 },
 {
  id: 'bench-press',
  title: 'Bench Press',
  description: 'Chest exercise...',
  muscles: 'chest'
 },
 {
  id: 'pull-ups',
  title: 'Pull Ups',
  description: 'Back and biceps exercise...',
  muscles: 'back'
 },
 {
  id: 'deadlifts',
  title: 'Deadlifts',
  description: 'Back and leg exercise...',
  muscles: 'back'
 },
 {
  id: 'squats',
  title: 'Squats',
  description: 'Legs exercise...',
  muscles: 'legs'
 }
]

通过比较 id，我想 return 一个新的对象数组，来自 btw 练习和 searchResult 的区别，没有重复！

Answer 1

您可以使用reduce and find

const exercises = [{id: 'pull-ups',title: 'Pull Ups',description: 'Back and biceps exercise...',muscles: 'back'},
{id: 'deadlifts',title: 'Deadlifts',description: 'Back and leg exercise...',muscles: 'back'},
{id: 'squats',title: 'Squats',description: 'Legs exercise...',muscles: 'legs'}]

const searchResult = [{id: 'overhead-press',title: 'Overhead Press',description: 'Delts exercise...',muscles: 'shoulders'},
{id: 'dips',title: 'Dips',description: 'Triceps exercise...',muscles: 'arms'},
{id: 'barbell-curls',title: 'Barbell Curls',description: 'Biceps exercise...',muscles: 'arms'},
{id: 'bench-press',title: 'Bench Press',description: 'Chest exercise...',muscles: 'chest'},
{id: 'pull-ups',title: 'Pull Ups',description: 'Back and biceps exercise...',muscles: 'back'},
{id: 'deadlifts',title: 'Deadlifts',description: 'Back and leg exercise...',muscles: 'back'},
{id: 'squats',title: 'Squats',description: 'Legs exercise...',muscles: 'legs'}]

let op = searchResult.reduce((op,inp) => {
  let add = exercises.find(e=> e.id === inp.id)
  if(!add){
    op[inp.id] = inp
  }
  return op
},{})

console.log(Object.values(op))

遍历 2 个对象数组和 return 单个对象数组的有效方法是什么？

What's the efficient way to iterate through 2 arrays of Objects and return a single array of objects?

javascript

arrays

loops

ecmascript-5

ecmascript-6