Excel Visual Basic 运行-初始化变量时出现错误“1004”

Excel Visual Basic Run-time error '1004' when initializing a variable

我正在学习 visual basic,我正在使用的脚本在初始化变量时出错 i

我不确定问题出在哪里,但我收到了错误消息:

Run-time error '1004': Application-defined or object-defined error

这是我的代码:

Sub excelmacro()

Sheets("Sheet1").Select
Range("A1").Select

Sheets("Sheet2").Select
Range("B1").Select

i = 1

While i <> 10
    If Len(ActiveCell.Value) > 1 Then
        Sheets("Sheet1").Select
        xname = Right(ActiveCell.Value, Len(ActiveCell.Value) - 6)
        xsalary = Right(ActiveCell.Value, Len(ActiveCell.Offset(2, 0).Value) - 8)
        xdesignation = Right(ActiveCell.Value, Len(ActiveCell.Offset(1, 0).Value) - 13)

        Sheets("Sheet2").Select
        ActiveCell.Value = xname
        ActiveCell.Offset(0, 1).Value = xdesig
        ActiveCell.Offset(0, 3).Value = xsalary

        ActiveCell.Offset(1, 0).Select
        Sheets("Sheet1").Select
        ActiveCell.Offset(3, 0).Select
    Else
        i = 10
    End If
Wend

End Sub

无论如何,您的代码中不需要变量 i!只需踢出初始化 i 的行即可。

循环中使用 i 的 if 语句基本上是为了跳出循环,可以缩短为:

While  Len(ActiveCell.Value) > 1 
    Sheets("Sheet1").Select
    xname = Right(ActiveCell.Value, Len(ActiveCell.Value) - 6)
    xsalary = Right(ActiveCell.Value, Len(ActiveCell.Offset(2, 0).Value) - 8)
    xdesignation = Right(ActiveCell.Value, Len(ActiveCell.Offset(1, 0).Value) - 13)

    Sheets("Sheet2").Select
    ActiveCell.Value = xname
    ActiveCell.Offset(0, 1).Value = xdesig
    ActiveCell.Offset(0, 3).Value = xsalary

    ActiveCell.Offset(1, 0).Select
    Sheets("Sheet1").Select
    ActiveCell.Offset(3, 0).Select

Wend

现在可能是开始练习 How to avoid using Select in Excel VBA macros 中详述的方法的好时机。

您的代码从 ActiveCell 中重复检索不同长度的最右侧字符,但使用活动单元格下方行中的值的长度来确定要检索的字符数。您似乎应该从用于确定长度的同一单元格中检索字符。

Sub excelmacro()
    Dim i As Long, xname As String, xsalary As String, xdesignation As String

    With Sheets("Sheet1")
        For i = 1 To .Cells(Rows.Count, "A").End(xlUp).Row Step 3
            If CBool(Len(.Cells(i, "A").Value)) Then
                xname = Right(.Cells(i, "A").Value, Len(.Cells(i, "A").Value) - 6)
                xdesignation = Right(.Cells(i + 1, "A").Value, Len(.Cells(i + 1, "A").Value) - 13)
                xsalary = Right(.Cells(i + 2, "A").Value, Len(.Cells(i + 2, "A").Value) - 8)

                With Sheets("Sheet2")
                    .Cells(Rows.Count, "B").End(xlUp).Offset(1, 0) = xname
                    .Cells(Rows.Count, "B").End(xlUp).Offset(0, 1) = xdesignation
                    .Cells(Rows.Count, "B").End(xlUp).Offset(0, 3) = xsalary
                End With

            End If
        Next i
    End With
End Sub

我保留了您对薪水的字符串变量的使用,尽管使用 double 类型的变量并使用 [=12 转换文本可能会更好=]包装。第二次使用 xdesig 而不是 xdesignation 已更正。