获取多次删除影响的行数

Question

当我在 PDO 中删除多行时，如何计算受影响的行数？这是我用来删除多行的技术：

$selected = $_POST['checkbox'];
    $N = count($selected);
    for ($i = 0; $i < $N; $i++) {
        $result = $dbh->prepare('DELETE FROM users WHERE id= :id');
        $result->bindParam(':id', $selected[$i], PDO::PARAM_INT);
        $result->execute();
    }

我试过了，但它总是返回 1:

$deleted = $result->rowCount();
    if ($deleted) {
        echo $deleted.' was deleted.';
    }

Answer 1

你是运行一个循环，所以每次调用都会删除 1；你需要添加一个计数器。

所以添加：

 $deleted += $result->rowCount();

循环内部

然后在外面：

if ($deleted) {
        echo $deleted.' was deleted.';
    }

Answer 2

如果 id 字段是唯一的，那么该语句最多可以影响 1 行。但是，您正在准备一条新语句并在循环中执行它。您应该尝试将删除的数量相加。

$deleted = 0;
for ($i = 0; $i < $N; $i++) {
    $result = $dbh->prepare('DELETE FROM users WHERE id= :id');
    $result->bindParam(':id', $selected[$i], PDO::PARAM_INT);
    $result->execute();
    $deleted = $deleted + $result->rowCount();
}
echo $deleted.' was deleted.';

Answer 3

这是一种一次性删除而不是运行多次删除的方法。这样 rowCount() 将显示删除的实际结果。

$selected = $_POST['checkbox'];

$placeholder = array();
$values = array();

foreach ($selected as $id) {
  $placeholder[] = ":".$id;
  $values[":".$id] = $id;
}


$sql = "Delete FROM users WHERE id IN (".implode(', ',$placeholder).") ";
$result = $dbh->prepare($sql);
$result->execute($values);

$deleted = $result->rowCount();

if ($deleted>0) {
    echo $deleted.' was deleted.';
}

获取多次删除影响的行数

Get the number of rows affected by multiple delete

php

mysql

pdo