剪刀石头布 Python 程序:winOrLose() 有两个参数(给定 0)

Rock Paper Scissors Python Program: winOrLose() takes two arguments (0 given)

我正在编写一个与用户一起玩剪刀石头布的程序。我必须 运行 该程序 5 次。我正在使用 python。每当我 运行 程序并输入 "R"、"S" 或 "P" 时,程序都会导致错误:

TypeError: winOrLose() takes exactly 2 arguments (0 given)  

下面是我的程序:

from myro import *  
from random import *  

def userOptions():  
    print "Press R for Rock"  
    print "Press P for Paper"
    print "Press S for Scissors"

choice = raw_input("Your choice is: ")

if choice == "R":
    return "Rock"
if choice == "P":
    return "Paper"
if choice == "S":
    return "Scissors"
else:
    userOptions()


def computerRandom():
    options = ["Rock", "Paper", "Scissors"]
    cGuess = randint(0,2)
    return options[cGuess]

def winOrLose(userChoice, computerChoice):
    if userChoice == computerChoice:
        return "Tie"
    if userChoice == "Rock" and computerChoice == "Paper":
        return "Computer Wins"
    if userChoice == "Paper" and computerChoice == "Scissors":
        return "Computer Wins"
    if userChoice == "Scissors" and computerChoice == "Rock":
        return "Computer Wins"
    else:
        return "User Wins"

    while True:
        userChoice = userOptions()
        computerChoice = computerRandom()
        print "User Chose: ", userChoice
        print "Computer Chose: ", computerChoice
        result = winOrLose(userChoice, computerChoice)
        if result == "Tie":
            print "It is a tie"
        elif result == "Computer Wins":
            print "Computer Wins"
        else:
            print "User Wins"

def main():
    for index in range(1,5,1):
        speak("Rock Paper Scissors Shoot")
        userOptions()
        computerRandom()
        winOrLose()

main()

请有人帮助我,我现在有点绝望,想知道如何解决这个问题。

谢谢

如错误中所述,您没有将参数传递给函数 winOrLose 在你的主要功能中

def main():
    for index in range(1,5,1):
        ...
        ...
        winOrLose()     # in this statement you are not passing any arguments

我认为您在调用 winOrLose() 时没有任何参数,尽管定义是 def winOrLose(userChoice, computerChoice):。您应该将值 userChoice, computerChoice 放入方法调用中。

如错误消息所示,您需要为 winOrLose 函数提供两个参数。您 return 来自 userOptions()computerRandom() 的值,但没有将这些值分配给任何变量:

def main():
    for index in range(1,5,1):
        speak("Rock Paper Scissors Shoot")
        user_choice = userOptions()
        computer_choice = computerRandom()
        winOrLose(user_choice, computer_choice)

main()

您没有在主函数中向它传递任何参数。

def main():
    for index in range(1,5,1):
        speak("Rock Paper Scissors Shoot")
        userOptions()
        computerRandom()
        winOrLose()

应该是:

def main():
    for index in range(1,5,1):
        speak("Rock Paper Scissors Shoot")
        userChoice = userOptions()
        computerChoice = computerRandom()
        winOrLose(userChoice, computerChoice)

另一个问题是,您尝试使用 for index in range(1,5,1) 运行 它 5 次,但是您在 winOrLose 函数中遇到了一个无限循环,所以您在调用后永远不会退出第一次:

def winOrLose(userChoice, computerChoice):
    if userChoice == computerChoice:
        return "Tie"
    if userChoice == "Rock" and computerChoice == "Paper":
        return "Computer Wins"
    if userChoice == "Paper" and computerChoice == "Scissors":
        return "Computer Wins"
    if userChoice == "Scissors" and computerChoice == "Rock":
        return "Computer Wins"
    else:
        return "User Wins"

    while True: # <=== infinite loop here.
        userChoice = userOptions()
        computerChoice = computerRandom()
        print "User Chose: ", userChoice
        print "Computer Chose: ", computerChoice
        result = winOrLose(userChoice, computerChoice)
        if result == "Tie":
            print "It is a tie"
        elif result == "Computer Wins":
            print "Computer Wins"
        else:
            print "User Wins"

再次播放的决定很可能根本不应该在 winOrLose 函数中,而应该在它自己的函数中。

您在 userOptions 函数中也遇到了缩进错误,尽管它可能只是从这里复制过来的。

def userOptions():  
    print "Press R for Rock"  
    print "Press P for Paper"
    print "Press S for Scissors"
# below code block should be indented too.
choice = raw_input("Your choice is: ")

if choice == "R":
    return "Rock"
if choice == "P":
    return "Paper"
if choice == "S":
    return "Scissors"
else:
    userOptions()