Dataweave 2 - 按行输出多个 JSON
Dataweave 2 - Output multiple JSON by line
我的输入是一个对象数组,我想映射到JSON对象.
我希望每个JSON对象每行一行并且JSON设置在相同的有效负载.
我的 Dataweave 代码:
%dw 2.0
output application/json indent = false
---
payload map (payload, indexOfPayload ) -> {
id: payload.externalid_c,
surname: payload.surname__c
platform: payload.platform__c
}
我想要的示例输出:
{"id": "demo", "surname": "anypoint", "platform": "testing"}
{"id": "demo2", "surname": "studio", "platform": "apple"}
{"id": "demo3", "surname": "windows", "platform": "microsoft"}
您好,您需要使用 write 函数并将其输出为纯文本,因为所需的输出无效 json
%dw 2.0
output text/plain
---
payload map ((value, index) -> write(value, "application/json", {indent: false})) joinBy "\n"
此示例向您展示了如何操作。
write
as json 首先使用 writer 属性 删除缩进,将列表项连接在一起,用新行分隔并输出为 text/plain(cannot使用 json 作为无效 json)
%dw 2.0
output text/plain
---
payload map ((item, index) ->
write({id: item.externalid_c,
surname: item.surname__c,
platform: item.platform__c
}, "application/json", {"indent":false})
) joinBy '\r'
我的输入是一个对象数组,我想映射到JSON对象.
我希望每个JSON对象每行一行并且JSON设置在相同的有效负载.
我的 Dataweave 代码:
%dw 2.0
output application/json indent = false
---
payload map (payload, indexOfPayload ) -> {
id: payload.externalid_c,
surname: payload.surname__c
platform: payload.platform__c
}
我想要的示例输出:
{"id": "demo", "surname": "anypoint", "platform": "testing"}
{"id": "demo2", "surname": "studio", "platform": "apple"}
{"id": "demo3", "surname": "windows", "platform": "microsoft"}
您好,您需要使用 write 函数并将其输出为纯文本,因为所需的输出无效 json
%dw 2.0
output text/plain
---
payload map ((value, index) -> write(value, "application/json", {indent: false})) joinBy "\n"
此示例向您展示了如何操作。
write
as json 首先使用 writer 属性 删除缩进,将列表项连接在一起,用新行分隔并输出为 text/plain(cannot使用 json 作为无效 json)
%dw 2.0
output text/plain
---
payload map ((item, index) ->
write({id: item.externalid_c,
surname: item.surname__c,
platform: item.platform__c
}, "application/json", {"indent":false})
) joinBy '\r'