连接 2 个变量以放入 json 无效

Question

我需要连接 2 个变量，但是当我执行 bash 代码时出现此错误 filters.api.malformed_request_body。

我需要获取当前 IP，以便能够向过滤器添加新 IP，那是因为我需要使用两个变量，$a 是我防火墙规则中的当前 IP， $b 是我要添加的新 IP。

To preserve existing values, issue a GET request and based on the response, determine which fields (and respective values) to include in your PUT request and that way, avoid any undesired overwrites.

代码：

a=122.16.89.10
b=137.77.77.77

curl -X PUT \
     -H "X-Auth-Email: EMAIL" \
     -H "X-Auth-Key: KEY" \
     -H "Content-Type: application/json" \
     -d '[
{
   "id": "ID",
   "paused": false,
   "expression": "(ip.src in {'$a'" "'$b'})",
   "description": "Block IP"
}
]' "https://api.cloudflare.com/client/v4/zones/ZONE/filters"

我也尝试过："(ip.src in {'$a $b'})" 和：

new_filter="$a $b"
...
...
"(ip.src in {'$new_filter'})"

如果我 echo $new_filter 它显示正确的结果：

new_filter="$a $b"
echo $new_filter
#122.16.89.10 137.77.77.77

当我使用变量 $new_filter 时它也显示这个错误 curl: (3) [globbing] unmatched close brace/bracket in column 13 第 13 行是这个 -H "Content-Type: application/json" \.

None 有效，为什么？我收到此错误：

{                                                                   
  "result": null,                                                   
  "success": false,                                                 
  "errors": [                                                       
    {                                                               
      "code": 10014,                                                
      "message": "filters.api.malformed_request_body"               
    }                                                               
  ],                                                                
  "messages": []                                                    
}

这有效："(ip.src in {'$a'})"。

Answer 1

好吧，让我们以您的第一个示例为例，将其修改为打印 JSON 正文：

export a=122.16.89.10
export b=137.77.77.77

echo '[
{
   "id": "ID",
   "paused": false,
   "expression": "(ip.src in {'$a'" "'$b'})",
   "description": "Block IP"
}
]'

输出是这样的：

{
   "id": "ID",
   "paused": false,
   "expression": "(ip.src in {122.16.89.10" "137.77.77.77})",
   "description": "Block IP"
}
]

可以看到JSON是无效的。 expression.

中的双引号不平衡

改为尝试 "expression": "(ip.src in {'$a' '$b'})", -- 这将产生有效的 JSON.

连接 2 个变量以放入 json 无效

Cocatenate 2 variables to put inside json is not working

api

bash

json

curl

cloudflare