如何修复 "Pointer being realloc'd was not allocated" 错误

Question

我有一个名为 House 的结构，它包含一个表示邻域的字符数组。我正在尝试读取房屋数据库并为具有相同街区的房屋创建一个数组。阅读部分工作正常，但是当我为一个社区创建一个新数组时，我的函数只进入循环 23 次并找到具有相同社区的前 23 个房屋并给出此错误。

pro(4740,0x10d06f5c0) malloc：* 对象 0x7ff724d00030 错误：未分配重新分配的指针 pro(4740,0x10d06f5c0) malloc: * set a breakpoint in malloc_error_break to debug

typedef struct house{
  int id;
  int lotarea;
  char street[5];
  int saleprice;
  char neighborhood[10];
  int yearbuilt;
  int overallqual;
  int overallcond;
  char kitchenqual[3];
} House;



House* get_neighborhoods(House house, House* array) {
printf("Get neighborhoods of house with id %d\n", house.id);

House* temp = array;
int counter = 1;


House* newarray = malloc(sizeof(House));

if (newarray == NULL) {
    printf("Malloc error...");
}


while (temp != NULL) {
    if (!strcmp(temp->neighborhood, house.neighborhood)) {


        if (counter > 1) {
            realloc(newarray, sizeof(House) * counter);
        }

        copy_house(newarray + counter - 1, temp);
        print_house(newarray[counter - 1]);
        counter++;
    }

    temp++;
}

return newarray;

}

Answer 1

您必须分配来自 realloc 的 return 值。你有

realloc(newarray, sizeof(House) * counter);

你调用它的秒次（在循环中），你之前传递给它的指针已经是freed了，但是你丢弃了新值.

newarray = realloc(newarray, sizeof(House) * counter);

理想情况下，您可以将 return 值分配给一个临时变量，这样您就可以检查 realloc 是否成功。

如何修复 "Pointer being realloc'd was not allocated" 错误

How to fix "Pointer being realloc'd was not allocated" error

c

malloc

realloc