如何修复 'on_exception() missing 1 required positional argument: exception'？

Question

我正在尝试使用 tweepy 从 Streaming API 流式传输推文并打印已流式传输的每条推文的文本。我收到以下错误：

TypeError: on_exception() missing 1 required positional argument: 'exception'

为什么我会收到这个消息，我该如何解决？

我遇到了类似的错误，它说要将请求库降级到 2.7。不用说，它没有用。

    class Authenticator():
             def authenticate_and_get_API_object(self):
                     auth = tweepy.OAuthHandler(consumerkey,consumersecret)               
                auth.set_access_token(accesstoken,accesstokensecret)

                     api = tweepy.API(auth)
                     return api

    class MyStreamListener(tweepy.StreamListener):
            def on_status(self,status):
                    print(status.text)

            def on_error(self,status_code):
                    if status_code==420:
                            return false

    if __name__ == "__main__":

            my_streamer = MyStreamListener()
            the_api = Authenticator().authenticate_and_get_API_object()
            myStream = tweepy.Stream(auth = the_api.auth, listener = MyStreamListener)
            myStream.filter(track=['python'])

如有任何帮助，我们将不胜感激

错误回溯：

Traceback (most recent call last):
  File "streamdemtweets.py", line 24, in <module>
    myStream.filter(track=['python'])
  File "/home/ansuman/.local/lib/python3.7/site-packages/tweepy/streaming.py", line 453, in filter
    self._start(is_async)
  File "/home/ansuman/.local/lib/python3.7/site-packages/tweepy/streaming.py", line 368, in _start
    self._run()
  File "/home/ansuman/.local/lib/python3.7/site-packages/tweepy/streaming.py", line 299, in _run
    self.listener.on_exception(exc_info[1])
TypeError: on_exception() missing 1 required positional argument: 'exception'

Answer 1

我已经解决了在实例化它时将 () 添加到 MyStreamListener:

myStream = tweepy.Stream(auth = the_api.auth, listener = MyStreamListener())

如何修复 'on_exception() missing 1 required positional argument: exception'？

How to fix 'on_exception() missing 1 required positional argument: exception'?

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