如何阻止我的 do while 循环接受除 "stop" 之外的每个字符串

Question

Write a main method that asks the user for an integer n which then allocates an array of ints of that size and stores that many integers as the user enters them. Once they are all entered, print them in the reverse order of how they were entered.

到目前为止，这就是我提出的（任何帮助将不胜感激）：

import java.util.ArrayList;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Array2D {

    public static void main(String[] args){
        Scanner num = new Scanner(System.in);
        ArrayList<Integer> number = new ArrayList<Integer>();
        int ber = 0;
        String stop = "";

        System.out.println("Type as many number as you like, to get in reverse order. When done typing number, type STOP: ");
        do{
            try{
                ber = num.nextInt();
                number.add(ber);
            }
            catch(InputMismatchException e){
                stop = num.nextLine();
                e.equals(stop);
            }




        }while(!(stop.equalsIgnoreCase("stop")));

Answer 1

将捕获更改为：

catch (InputMismatchException e) {
    if(stop.equalsIgnoreCase("stop")){
       continue;
    }
    stop = num.nextLine();
    e.equals(stop);
}

并以相反的顺序打印它们：

for (int i= (number.size()-1); i >= 0; i--) {
    System.out.println(number.get(i));
}

Answer 2

问题陈述不需要arraylist。只是使用数组的基本代码逻辑。

void print reverse(int n){
    int[] arr = new int[n];
    Scanner sc = new Scanner(System.in);
    for (int i = 0; i < n; ++i){
        arr[i] = sc.nextInt();
    }
    for (int i = n-1; i >= 0; --i){
        System.out.println(arr[i]);
    }
}

Answer 3

以相反的顺序打印它们

for (int i = number.size() - 1; i >= 0; i--) {
    System.out.println(number.get(i));
}

Answer 4

你的问题的任务是要求你做这样的事情（甚至不需要处理用户写入 stop 或其他不正确数据的情况，但如果你愿意，你可以处理它们）。

//ask user for array size
int n = getInt();
//create array for n integers
int[] array = new int[n];
//read n integers from user
for (i in 0..n-1)
    tmp = readInt()
    //and store them in array
    put tmp in array at position i

//print content of array backwards
for (i in n-1..0)
    print(i-th element from array)

Answer 5

int n = 0;
Scanner num = new Scanner(System.in);
System.out.println("How many numbers do you want to display: ");
n = num.nextInt();
int[] number = new int[n];

System.out.println("Enter the numbers: ");

for(int i = 0; i<n; i++){
    number[i] = num.nextInt();      
}

System.out.println("Here they are in reverse! ");

for(int i = n-1; i >= 0; --i){
    System.out.println(number[i]);
}

如何阻止我的 do while 循环接受除 "stop" 之外的每个字符串

How to stop my do while loop from accepting every single string except "stop"

java

arrays

string

integer

arraylist