使用来自同一列的数据计算百分比 SQL 语句

Question

我正在尝试计算百分比。计算公式如下：

%=(Totale time AAN / (Totale time AAN + totale time UIT))*100

Table 看起来像这样：

+------------+-------------+
| DATA_SOORT | DATA_WAARDE |
+------------+-------------+
| TEMP       |          22 |
| AAN        |       14200 |
| UIT        |       10200 |
| HUM        |          44 |
| AAN        |       10000 |
| UIT        |       13000 |
| TEMP       |          23 |
+------------+-------------+

DATA_WAARDE 来自 AAN 和 UIT 以毫秒为单位。

我试过：

     SELECT sum((((`DATA_WAARDE`/1000) 
     FROM `IOT_DATA` 
     WHERE `DATA_SOORT`="AAN")/sum(`DATA_WAARDE`/1000) 
     FROM `IOT_DATA` 
     WHERE (`DATA_SOORT`="UIT" OR `DATA_SOORT`="AAN"))*100)

上述 table 的预期结果应为 51,05%。

Answer 1

只需使用case when，SQL如下：

select * from iot_data;
 data_soort | data_waarde 
------------+-------------
 TEMP       |          22
 AAN        |       14200
 UIT        |       10200
 HUM        |          44
 AAN        |       10000
 UIT        |       13000
(6 rows)

 select
     concat(round(sum(case when data_soort='AAN' then data_waarde else null end)*100.0/sum(case when data_soort in ('AAN','UIT') then data_waarde else null end),2),'%') as percent
 from
     iot_data;
+---------+
| percent |
+---------+
| 51.05%  |
+---------+
1 row in set (0.02 sec)

Answer 2

尝试：

select `DATA_WAARDE`*100/SUM(`DATA_WAARDE`) OVER(PARTITION BY 1) from `IOT_DATA` WHERE (`DATA_SOORT`="UIT" OR `DATA_SOORT`="AAN")

你也可以将它封装到另一个查询中 returns 只是 AAN

Answer 3

SELECT SUM(IF(DATA_SOORT='AAN', `DATA_WAARDE`, NULL))
/ SUM(`DATA_WAARDE`) * 100
FROM `IOT_DATA` 
WHERE `DATA_SOORT` IN ('UIT', 'AAN')

看到它在 sqlfiddle

Answer 4

我喜欢使用 avg():

select avg( data_waarde = 'ANN') * 100 as percent
from iot_data
where data_soort in ('UIT', 'AAN');

使用来自同一列的数据计算百分比 SQL 语句

Calculate percentage SQL statement in with data from the same column

mysql

sql

percentage