按 Javascript 中的 ID 过滤 json 个对象

Question

我有一个 JSON return 对象数组，但我想做的是 return 按 ID 过滤的对象数组。这是我到目前为止构建的代码：

    let objComedien3=[];
      let i=0;

      for (var prop in bc) {
        objComedien3[i] = await app.models.cm_comediens_extraits_mp3.find({ where: { idMedia: bc[prop]} } );
        //here the result is giving me an array of arrays of objects so I had to do this :
        objComedien3[i]= Object.assign({}, objComedien3[i]);
        i++;
      }
      return objComedien3;

我找到的最终结果是这样的：

[
  {
    "0": {
      "idSon": 33274,
      "idMedia": 42084,
      "qfDiffusion": null,
      "qfAccent": null,
      "qfAge": 169,
      "qfCartoon": null,
      "qfDoublage": null,
      "qfInterpretation1": 194,
      "qfInterpretation2": 194,
      "qfInterpretation3": 193,
      "qfImitation": null,
      "qfLangue": 145,
      "qfTimbre": 237,
      "qfType": 245,
      "qfGenre": "Masculin",
      "description": "Techno Music"
    }
  },
  {
    "0": {
      "idSon": 33275,
      "idMedia": 42086,
      "qfDiffusion": null,
      "qfAccent": null,
      "qfAge": 240,
      "qfCartoon": null,
      "qfDoublage": null,
      "qfInterpretation1": 196,
      "qfInterpretation2": 195,
      "qfInterpretation3": 247,
      "qfImitation": null,
      "qfLangue": 147,
      "qfTimbre": 236,
      "qfType": 176,
      "qfGenre": "Masculin",
      "description": "Techno Music"
    }
  }
]

一切都很好，除了我想用 idSon 替换 0 并且我不知道如何使用 Object.assign 或使用 javascript 的任何其他函数来管理它。任何帮助，将不胜感激。非常感谢

Answer 1

试试这个：

 let objComedien3=[];
      let i=0;

      for (var prop in bc) {
        objComedien3[i] = await app.models.cm_comediens_extraits_mp3.find({ where: { idMedia: bc[prop]} } );
        //here the result is giving me an array of arrays of objects so I had to do this :
        let data= {}
        data[objComedien3[i][0]['idSon']] = objComedien3[i][0]
        objComedien3[i]= Object.assign({}, data);
        i++;
      }
      return objComedien3;

Answer 2

您可以使用 object 而不是 array 来执行此操作，这样您就可以输入 idSon 键作为限定符而不是 [=12= 中的索引]:

let objComedien3 = {};

for (var prop in bc) {
  let result = await app.models.cm_comediens_extraits_mp3.find({ where: { idMedia: bc[prop]} } );
  let clonedResult = Object.assign({}, result[0]);
  objComedien3[clonedResult.idSon] = clonedResult;
}

return objComedien3;

Answer 3

 for (let t of test) {

    //replace your "0" with new "idSon"

    t["idSon"] = t["0"];

    //delete your "0" property object

    delete t["0"];

}

//filter based on Id in this example I Used 33275

let filteredData: any = test.filter((o: any) => o["idSon"].idSon == 33275);

Answer 4

我知道有一个已经被接受的答案，但要以正确的方式执行此操作，您应该先获得总结果然后再进行处理。

const dataset = await app.models.cm_comediens_extraits_mp3.find(
    { where: { idMedia: {inq: bc} } }//which gets all the media
).then((data)=>{//it is an array already
    return data.reduce((p,c)=>{
        p[c.idSon] = c;//or c.__data if you want the data. Or Object.assign
        return p;
    },{})
})

这样就不用每次都查询了

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