无法在 Webpack 中输出动态 SCSS 入口点
Can't Output Dynamic SCSS Entry points in Webpack
我正在使用 Webpack 4,我正在尝试查看一个文件夹以找到所有 scss 文件并为找到的每个文件动态创建一个入口点。当我看到函数正在返回时,它似乎正在返回我所需要的,但是没有 css 文件从函数中输出,只有一个用于第一个入口点备用:
我不明白我做错了什么。感谢您提供的任何帮助。
const departmentStyles = pattern => glob
.sync(pattern)
.reduce((entries, filename) => {
const [, name] = filename.match(/([^/]+)\.scss$/)
return { ...entries, [name]: filename }
}, {})
console.log('Departments', departmentStyles('./src/scss/alternate/departments/*.scss'))
When I log out the return value of department style I receive:
/*
Departments { alt1: './src/scss/alternate/departments/alt1.scss',
alt2: './src/scss/alternate/departments/alt2.scss',
alt: './src/scss/alternate/departments/alt3.scss', }
*/
module.exports = {
entry: {
...departmentStyles('./scss/alternate/departments/*.scss'),
},
output: {
path: path.join(__dist, 'alternate'),
filename: 'js/[name].js',
chunkFilename: 'js/[name].chunk.js',
},
plugins: [
new MiniCssExtractPlugin({
filename: 'css/[name].css',
chunkFilename: 'css/[name].css'
})
]
}
经过反复试验,我找到了解决方案。我修改了首先检索文件的方式,然后将对象添加到 webpack 入口点
const entryObject = {}
// For each file in the glob
departments.forEach(file => {
// Will return just the file name without extension
const name = file.match(/(?<=\/departments\/)(.*)(?=.*\.scss)/g)
// Replace ./src with ./ so the path will resolve on build
file = file.replace('./src/', './')
// Build the entry object
entryObject[name] = file
})
// 上面创建了一个入口对象:name: 'filepath/file.css'
然后在我的入口点中,我只需添加 entryObject
module.exports = {
entry: {
tri: './js/tri.js',
entryObject
}
/* Rest of the webpack stuff */
}
我正在使用 Webpack 4,我正在尝试查看一个文件夹以找到所有 scss 文件并为找到的每个文件动态创建一个入口点。当我看到函数正在返回时,它似乎正在返回我所需要的,但是没有 css 文件从函数中输出,只有一个用于第一个入口点备用:
我不明白我做错了什么。感谢您提供的任何帮助。
const departmentStyles = pattern => glob
.sync(pattern)
.reduce((entries, filename) => {
const [, name] = filename.match(/([^/]+)\.scss$/)
return { ...entries, [name]: filename }
}, {})
console.log('Departments', departmentStyles('./src/scss/alternate/departments/*.scss'))
When I log out the return value of department style I receive:
/*
Departments { alt1: './src/scss/alternate/departments/alt1.scss',
alt2: './src/scss/alternate/departments/alt2.scss',
alt: './src/scss/alternate/departments/alt3.scss', }
*/
module.exports = {
entry: {
...departmentStyles('./scss/alternate/departments/*.scss'),
},
output: {
path: path.join(__dist, 'alternate'),
filename: 'js/[name].js',
chunkFilename: 'js/[name].chunk.js',
},
plugins: [
new MiniCssExtractPlugin({
filename: 'css/[name].css',
chunkFilename: 'css/[name].css'
})
]
}
经过反复试验,我找到了解决方案。我修改了首先检索文件的方式,然后将对象添加到 webpack 入口点
const entryObject = {}
// For each file in the glob
departments.forEach(file => {
// Will return just the file name without extension
const name = file.match(/(?<=\/departments\/)(.*)(?=.*\.scss)/g)
// Replace ./src with ./ so the path will resolve on build
file = file.replace('./src/', './')
// Build the entry object
entryObject[name] = file
})
// 上面创建了一个入口对象:name: 'filepath/file.css'
然后在我的入口点中,我只需添加 entryObject
module.exports = {
entry: {
tri: './js/tri.js',
entryObject
}
/* Rest of the webpack stuff */
}