未定义的变量:mysql PHP 中的名称
Undefined variable: Name in mysql PHP
enter image description here如果登录信息错误,系统会正确显示"Fail login"。
但是当详细信息正确时,系统将在 行显示“C:\Users\Alex\Desktop\OSMAD.5\root\Project\test3.php 25
登录失败
这里是 PHP 文本
<?php
$host = "127.0.0.1";
$username = "root";
$password = "usbw";
$dbname = "forum_system";
// Connect to server
$connect = mysql_connect($host, $username, $password)
or die ("Sorry, unable to connect database server");
$dbselect = mysql_select_db($dbname,$connect)
or die ("Sorry, unable to connect database");
$Name = $_POST['Name'];
$Password = $_POST['Password'];
$result = mysql_query("select * from users where name = '$Name' and
password = '$Password'")
or die("Sorry, query failed".mysql_error());
$row = mysql_fetch_array($result);
if ( $row['Name'] == $Name && $row['Password'] == $Password ) {
echo "welcome";
} else {
echo "Fail login";
}
?>
好吧 MySQL table 列名是区分大小写的。因此,您应该使用 $row['Name'] 和 $row['Password'] 而不是 $row['name'] 和 $row['password']。所以行:
if ( $row['Name'] == $Name && $row['Password'] == $Password )
应替换为:
if ( $row['name'] == $Name && $row['password'] == $Password )
中删除
enter image description here如果登录信息错误,系统会正确显示"Fail login"。
但是当详细信息正确时,系统将在 行显示“C:\Users\Alex\Desktop\OSMAD.5\root\Project\test3.php 25
登录失败
这里是 PHP 文本
<?php
$host = "127.0.0.1";
$username = "root";
$password = "usbw";
$dbname = "forum_system";
// Connect to server
$connect = mysql_connect($host, $username, $password)
or die ("Sorry, unable to connect database server");
$dbselect = mysql_select_db($dbname,$connect)
or die ("Sorry, unable to connect database");
$Name = $_POST['Name'];
$Password = $_POST['Password'];
$result = mysql_query("select * from users where name = '$Name' and
password = '$Password'")
or die("Sorry, query failed".mysql_error());
$row = mysql_fetch_array($result);
if ( $row['Name'] == $Name && $row['Password'] == $Password ) {
echo "welcome";
} else {
echo "Fail login";
}
?>
好吧 MySQL table 列名是区分大小写的。因此,您应该使用 $row['Name'] 和 $row['Password'] 而不是 $row['name'] 和 $row['password']。所以行:
if ( $row['Name'] == $Name && $row['Password'] == $Password )
应替换为:
if ( $row['name'] == $Name && $row['password'] == $Password )
中删除