model.matrix 来自 r 中的列表
model.matrix from lists in r
我正在尝试将因子列表转换为矩阵,例如:
我的列表:
[[1]]
[1] "RA" "FZFG" "BR"
[[2]]
[1] "RA"
[[3]]
[1] ""
[[4]]
[1] ""
到
RA FZFG BR
1 1 1
1 0 0
0 0 0
0 0 0
我尝试执行以下操作:
allFactors<-c("RA","FZFG","BR")
mat<-model.matrix(~allFactors, data =myLists)
但出现错误:
Error in data.frame(c("RA", "FZFG", "BR"), "RA", "", "", "", "",
c("RA", : arguments imply differing number of rows: 3, 1, 2, 4, 5,
7, 6, 8, 9
感谢任何帮助。
一个选项是
library(qdapTools)
mtabulate(myLists)[-1]
或使用base R
table(stack(setNames(myLists, seq_along(myLists)))[2:1])[,-1]
基本 R
选项:
level = unique(unlist(lst))
do.call(rbind, lapply(lst, function(u) table(factor(u, levels=level))))
我正在尝试将因子列表转换为矩阵,例如:
我的列表:
[[1]]
[1] "RA" "FZFG" "BR"
[[2]]
[1] "RA"
[[3]]
[1] ""
[[4]]
[1] ""
到
RA FZFG BR
1 1 1
1 0 0
0 0 0
0 0 0
我尝试执行以下操作:
allFactors<-c("RA","FZFG","BR")
mat<-model.matrix(~allFactors, data =myLists)
但出现错误:
Error in data.frame(c("RA", "FZFG", "BR"), "RA", "", "", "", "", c("RA", : arguments imply differing number of rows: 3, 1, 2, 4, 5, 7, 6, 8, 9
感谢任何帮助。
一个选项是
library(qdapTools)
mtabulate(myLists)[-1]
或使用base R
table(stack(setNames(myLists, seq_along(myLists)))[2:1])[,-1]
基本 R
选项:
level = unique(unlist(lst))
do.call(rbind, lapply(lst, function(u) table(factor(u, levels=level))))