如何在 Java 中构建 JSON 数据

Question

我想 POST JSON 使用 Apache HttpClient 请求。但是 Json 数据有点复杂，我想发送到目标系统。以下是我要发送

的 json

{
  "name":"xyz",
  "id":"428",
"mailId":
  [
   "mailme@mail.com"
  ],
  "bundle1":
  {
      "opwarden":
      {
         "number":"132344345",
         "title":"title"
      }     
  }
}

在 Java 中收缩超过 json 数据的最好和最简单的方法是什么？

Answer 1

我建议使用 JACKSON 对象映射器。如果你不想重新创建上面的模型结构写 pojos。

可以在这里找到一个很好的教程enter link description here

你基本上是这样使用的：

ObjectMapper objectMapper = new ObjectMapper();
String jsonRepresentation = objectMapper.writeValueAsString( anyObject );

如上所述，anyObject 也可以是 Map key/values，值也可以是 maps。

您的具体用例如下：

    ObjectMapper m = new ObjectMapper();

    Map<String, Object> input = new HashMap<String, Object>();
    input.put( "name", "xyz" );
    input.put( "id", "428" );
    input.put( "mailId", new String[] { "mailme@mail.com" } );

    Map<String, Object> opwarden = new HashMap<String, Object>();
    opwarden.put( "number", "132344345" );
    opwarden.put( "title", "title" );

    Map<String, Object> bundle1 = new HashMap<String, Object>();
    bundle1.put( "opwarden", opwarden );

    input.put( "bundle1" , bundle1 );

    String json = m.writeValueAsString( input );

Answer 2

使用 POJO 和 ObjectMapper 杰克逊：

public class Data {

    private final String name;
    private final String id;
    private final List<String> mailId;
    private final List<Opwarden> bundle1;

    public Data(final String name, final String id, final List<String> mailId, final List<Opwarden>     bundle1) {
        this.name = name;
        this.id = id;
        this.mailId = mailId;
        this.bundle1 = bundle1;
    }

    public String getName() {
        return name;
    }

    public String getId() {
        return id;
    }

    public List<String> getMailId() {
        return mailId;
    }

    public List<Opwarden> getBundle1() {
        return bundle1;
    }
}

和奥普瓦登：

public class Opwarden {

    private final String number;
    private final String title;

    public Opwarden(final String number, final String title) {
        this.number = number;
        this.title = title;
    }

    public String getNumber() {
        return number;
    }

    public String getTitle() {
        return title;
    }
}

您可以通过以下方式创建 JSON：

ObjectMapper objectMapper = new ObjectMapper();
Data data = new Data("xyz", "428", List.of("mailme@mail.com"), List.of(new Opwarden("132344345", "title")));
System.out.println(objectMapper.writeValueAsString(data));

输出：

{
    "name": "xyz",
    "id": "428",
    "mailId": [
        "mailme@mail.com"
    ],
    "bundle1": [
        {
            "number": "132344345",
            "title": "title"
        }
    ]
}

如何在 Java 中构建 JSON 数据

How to construct JSON data in Java

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json

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apache-httpclient-4.x