在 SwiftUI 中使用十六进制颜色

Question

在 UIKit 中，我们可以使用扩展来为几乎所有内容设置十六进制颜色。 https://www.hackingwithswift.com/example-code/uicolor/how-to-convert-a-hex-color-to-a-uicolor

但是当我尝试在 SwiftUI 上执行此操作时，这是不可能的，看起来 SwiftUI 没有将 UIColor 作为参数。

    Text(text)
        .color(UIColor.init(hex: "FFF"))

错误信息：

Cannot convert value of type 'UIColor' to expected argument type 'Color?'

我什至尝试过 Color 的扩展，而不是 UIColor，但我没有任何运气

我的颜色扩展：

导入 SwiftUI

extension Color {
    init(hex: String) {
        let scanner = Scanner(string: hex)
        scanner.scanLocation = 0
        var rgbValue: UInt64 = 0
        scanner.scanHexInt64(&rgbValue)

        let r = (rgbValue & 0xff0000) >> 16
        let g = (rgbValue & 0xff00) >> 8
        let b = rgbValue & 0xff

        self.init(
            red: CGFloat(r) / 0xff,
            green: CGFloat(g) / 0xff,
            blue: CGFloat(b) / 0xff, alpha: 1
        )
    }
}

错误信息：

Incorrect argument labels in call (have 'red:green:blue:alpha:', expected '_:red:green:blue:opacity:')

Answer 1

你就快完成了，你使用了错误的初始化参数：

extension Color {
    init(hex: String) {
        let hex = hex.trimmingCharacters(in: CharacterSet.alphanumerics.inverted)
        var int: UInt64 = 0
        Scanner(string: hex).scanHexInt64(&int)
        let a, r, g, b: UInt64
        switch hex.count {
        case 3: // RGB (12-bit)
            (a, r, g, b) = (255, (int >> 8) * 17, (int >> 4 & 0xF) * 17, (int & 0xF) * 17)
        case 6: // RGB (24-bit)
            (a, r, g, b) = (255, int >> 16, int >> 8 & 0xFF, int & 0xFF)
        case 8: // ARGB (32-bit)
            (a, r, g, b) = (int >> 24, int >> 16 & 0xFF, int >> 8 & 0xFF, int & 0xFF)
        default:
            (a, r, g, b) = (1, 1, 1, 0)
        }

        self.init(
            .sRGB,
            red: Double(r) / 255,
            green: Double(g) / 255,
            blue:  Double(b) / 255,
            opacity: Double(a) / 255
        )
    }
}

Answer 2

下面的另一种方法是将 Int 用作十六进制，当然，如果您愿意，可以将其更改为 String。

extension Color {
    init(hex: UInt, alpha: Double = 1) {
        self.init(
            .sRGB,
            red: Double((hex >> 16) & 0xff) / 255,
            green: Double((hex >> 08) & 0xff) / 255,
            blue: Double((hex >> 00) & 0xff) / 255,
            opacity: alpha
        )
    }
}

使用示例：

Color(hex: 0x000000)
Color(hex: 0x000000, alpha: 0.2)

Answer 3

这是我的解决方案的 Playground。它在回退后添加回退，并且仅依赖 hexString 的颜色和 alpha。

import SwiftUI

extension Color {
    init(hex string: String) {
        var string: String = string.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)
        if string.hasPrefix("#") {
            _ = string.removeFirst()
        }

        // Double the last value if incomplete hex
        if !string.count.isMultiple(of: 2), let last = string.last {
            string.append(last)
        }

        // Fix invalid values
        if string.count > 8 {
            string = String(string.prefix(8))
        }

        // Scanner creation
        let scanner = Scanner(string: string)

        var color: UInt64 = 0
        scanner.scanHexInt64(&color)

        if string.count == 2 {
            let mask = 0xFF

            let g = Int(color) & mask

            let gray = Double(g) / 255.0

            self.init(.sRGB, red: gray, green: gray, blue: gray, opacity: 1)

        } else if string.count == 4 {
            let mask = 0x00FF

            let g = Int(color >> 8) & mask
            let a = Int(color) & mask

            let gray = Double(g) / 255.0
            let alpha = Double(a) / 255.0

            self.init(.sRGB, red: gray, green: gray, blue: gray, opacity: alpha)

        } else if string.count == 6 {
            let mask = 0x0000FF
            let r = Int(color >> 16) & mask
            let g = Int(color >> 8) & mask
            let b = Int(color) & mask

            let red = Double(r) / 255.0
            let green = Double(g) / 255.0
            let blue = Double(b) / 255.0

            self.init(.sRGB, red: red, green: green, blue: blue, opacity: 1)

        } else if string.count == 8 {
            let mask = 0x000000FF
            let r = Int(color >> 24) & mask
            let g = Int(color >> 16) & mask
            let b = Int(color >> 8) & mask
            let a = Int(color) & mask

            let red = Double(r) / 255.0
            let green = Double(g) / 255.0
            let blue = Double(b) / 255.0
            let alpha = Double(a) / 255.0

            self.init(.sRGB, red: red, green: green, blue: blue, opacity: alpha)

        } else {
            self.init(.sRGB, red: 1, green: 1, blue: 1, opacity: 1)
        }
    }
}

let gray0 = Color(hex: "3f")
let gray1 = Color(hex: "#69")
let gray2 = Color(hex: "#6911")
let gray3 = Color(hex: "fff")
let red = Color(hex: "#FF000044s")
let green = Color(hex: "#00FF00")
let blue0 = Color(hex: "0000FF")
let blue1 = Color(hex: "0000F")

用于从 Color 获取 hexString.. 好吧，这不是 public API。为此，我们仍然需要依赖 UIColor 实现。

PS：我看到了下面的组件解决方案..但是如果API以后有变化，我的版本会更稳定一些。

Answer 4

试试这个

extension Color {
    init(hex: Int, opacity: Double = 1.0) {
        let red = Double((hex & 0xff0000) >> 16) / 255.0
        let green = Double((hex & 0xff00) >> 8) / 255.0
        let blue = Double((hex & 0xff) >> 0) / 255.0
        self.init(.sRGB, red: red, green: green, blue: blue, opacity: opacity)
    }
}

使用

Text("Hello World!")
            .background(Color(hex: 0xf5bc53))

Text("Hello World!")
            .background(Color(hex: 0xf5bc53, opacity: 0.8))

Answer 5

用法
UIColor.init(hex: "f2000000")
UIColor.init(hex: "#f2000000")
UIColor.init(hex: "000000")
UIColor.init(hex: "#000000")

extension UIColor {
public convenience init(hex:String) {
var cString:String = hex.trimmingCharacters(in: .whitespacesAndNewlines).uppercased()
    
    if (cString.hasPrefix("#")) {
        cString.remove(at: cString.startIndex)
    }
    var r: CGFloat = 0.0
    var g: CGFloat = 0.0
    var b: CGFloat = 0.0
    var a: CGFloat = 1.0
    
    var rgbValue:UInt64 = 0
    Scanner(string: cString).scanHexInt64(&rgbValue)
    
    if ((cString.count) == 8) {
        r = CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0
        g =  CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0
        b = CGFloat((rgbValue & 0x0000FF)) / 255.0
        a = CGFloat((rgbValue & 0xFF000000)  >> 24) / 255.0
        
    }else if ((cString.count) == 6){
        r = CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0
        g =  CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0
        b = CGFloat((rgbValue & 0x0000FF)) / 255.0
        a =  CGFloat(1.0)
    }
    
    
    self.init(  red: r,
                green: g,
                blue: b,
                alpha: a
    )
} }

Answer 6

SwiftUI 从十六进制（3、4、6、8 个字符）创建颜色支持 #、alpha、web constants 和 UIColor constants。使用示例如下。

Swift Package iOS 14+ 包括对 Color 十六进制、随机、CSS 颜色和用户默认值的支持。

Answer 7

我还通过 hackingwithswift 使用了 UIColor 的解决方案。这是 Color:

的改编版本

init?(hex: String) {
    var hexSanitized = hex.trimmingCharacters(in: .whitespacesAndNewlines)
    hexSanitized = hexSanitized.replacingOccurrences(of: "#", with: "")

    var rgb: UInt64 = 0

    var red: Double = 0.0
    var green: Double = 0.0
    var blue: Double = 0.0
    var opacity: Double = 1.0

    let length = hexSanitized.count

    guard Scanner(string: hexSanitized).scanHexInt64(&rgb) else { return nil }

    if length == 6 {
        red = Double((rgb & 0xFF0000) >> 16) / 255.0
        green = Double((rgb & 0x00FF00) >> 8) / 255.0
        blue = Double(rgb & 0x0000FF) / 255.0

    } else if length == 8 {
        red = Double((rgb & 0xFF000000) >> 24) / 255.0
        green = Double((rgb & 0x00FF0000) >> 16) / 255.0
        blue = Double((rgb & 0x0000FF00) >> 8) / 255.0
        opacity = Double(rgb & 0x000000FF) / 255.0

    } else {
        return nil
    }

    self.init(.sRGB, red: red, green: green, blue: blue, opacity: opacity)
}

Answer 8

extension Color {
  init(_ hex: UInt, alpha: Double = 1) {
    self.init(
      .sRGB,
      red: Double((hex >> 16) & 0xFF) / 255,
      green: Double((hex >> 8) & 0xFF) / 255,
      blue: Double(hex & 0xFF) / 255,
      opacity: alpha
    )
  }
}

那么，你可以这样使用它：

let red = Color(0xFF0000)
let green = Color(0x00FF00)
let translucentMagenta = Color(0xFF00FF, alpha: 0.4)

第二个扩展允许从十六进制字符串构建颜色，涵盖大多数已知格式。它允许：

指定带或不带前导 # 的颜色。灰色阴影的 2 位数字格式。 shorthand 6 位格式的 3 位格式。带 alpha 的灰色的 4 位数字格式。 RGB 的 6 位数字格式。 RGBA 的 8 位格式。对于所有无效格式自动 returns nil。

extension Color {
  init?(_ hex: String) {
    var str = hex
    if str.hasPrefix("#") {
      str.removeFirst()
    }
    if str.count == 3 {
      str = String(repeating: str[str.startIndex], count: 2) 
        + String(repeating: str[str.index(str.startIndex, offsetBy: 1)], count: 2) 
        + String(repeating: str[str.index(str.startIndex, offsetBy: 2)], count: 2)
    } else if !str.count.isMultiple(of: 2) || str.count > 8 {
      return nil
    }
    let scanner = Scanner(string: str)
    var color: UInt64 = 0
    scanner.scanHexInt64(&color)
    if str.count == 2 {
      let gray = Double(Int(color) & 0xFF) / 255
      self.init(.sRGB, red: gray, green: gray, blue: gray, opacity: 1)
    } else if str.count == 4 {
      let gray = Double(Int(color >> 8) & 0x00FF) / 255
      let alpha = Double(Int(color) & 0x00FF) / 255
      self.init(.sRGB, red: gray, green: gray, blue: gray, opacity: alpha)
    } else if str.count == 6 {
      let red = Double(Int(color >> 16) & 0x0000FF) / 255
      let green = Double(Int(color >> 8) & 0x0000FF) / 255
      let blue = Double(Int(color) & 0x0000FF) / 255
      self.init(.sRGB, red: red, green: green, blue: blue, opacity: 1)
    } else if str.count == 8 {
      let red = Double(Int(color >> 24) & 0x000000FF) / 255
      let green = Double(Int(color >> 16) & 0x000000FF) / 255
      let blue = Double(Int(color >> 8) & 0x000000FF) / 255
      let alpha = Double(Int(color) & 0x000000FF) / 255
      self.init(.sRGB, red: red, green: green, blue: blue, opacity: alpha)
    } else {
      return nil
    }
  }
}

下面是一些示例颜色，展示了所有支持的格式：

let gray1 = Color("4f")
let gray2 = Color("#68")
let gray3 = Color("7813")
let red = Color("f00")
let translucentGreen = Color("#00FF0066")
let blue = Color("0000FF")
let invalid = Color("0000F")

祝你好运;)

Answer 9

您可以将此扩展程序用于 UIColor

extension UIColor {
    convenience init(hexaString: String, alpha: CGFloat = 1) {
        let chars = Array(hexaString.dropFirst())
        self.init(red:   .init(strtoul(String(chars[0...1]),nil,16))/255,
                  green: .init(strtoul(String(chars[2...3]),nil,16))/255,
                  blue:  .init(strtoul(String(chars[4...5]),nil,16))/255,
                  alpha: alpha)}
}

Usage Example:

let lightGoldColor  = UIColor(hexaString: "#D6CDB2")

Test Code:

Resource

在 SwiftUI 中使用十六进制颜色

Use Hex color in SwiftUI

uicolor

ios

swiftui