while 循环运行错误的次数

Question

我在使用 while-loop 时遇到问题，因为 if 语句的目的是检查按钮是否为空（如果不重复）。但是，如果整个 if 语句位于 while-loop 中，它会在运行代码后首次显示大约 4 个按钮。

case HINT:
    Random random = new Random();
    int size = SizeOfPuzzle.currentRows;
    int randomNumber1 = random.nextInt(size);
    int randomNumber2 = random.nextInt(size);
    if (puzzlePanel.arrayOfButtons[randomNumber1][randomNumber2].getText().isEmpty()) {
       puzzlePanel.arrayOfButtons[randomNumber1][randomNumber2].setText(puzzle.getSingleLetter(randomNumber1, randomNumber2) + "");
    }else {
       boolean finished = true;
       while (!finished) {
          randomNumber1 = random.nextInt(size);
          randomNumber2 = random.nextInt(size);
          if (puzzlePanel.arrayOfButtons[randomNumber1][randomNumber2].getText().isEmpty()) {
              puzzlePanel.arrayOfButtons[randomNumber1][randomNumber2].setText(puzzle.getSingleLetter(randomNumber1, randomNumber2) + "");
              break;
          }

       }
    }
break;

Answer 1

如果你想进入while，你必须初始化finished到false，然后当工作完成后设置finished到true退出循环

boolean finished = false;
while (!finished) {
//     ↑ ↑ ↑ ↑ ↑ →→→→→→ this means loop while finished == false 
    randomNumber1 = random.nextInt(size);
    randomNumber2 = random.nextInt(size);
    if (puzzlePanel.arrayOfButtons[randomNumber1][randomNumber2].getText().isEmpty()) {
        puzzlePanel.arrayOfButtons[randomNumber1][randomNumber2].setText(puzzle.getSingleLetter(randomNumber1, randomNumber2) + "");
        finished = true;
     }    
 }

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