Error: TypeError: init() takes 1 positional argument but 2 were given

Question

我绝对是Python初学者，不明白下面几行的问题。

class Base:
    def __init__(self, x):
        print("Base")
        self.x = x

class A(Base):
    def __init__(self):
        super(A, self).__init__(1)
        print("A")
class B(Base):
    def __init__(self):
        super(B, self).__init__(2)
        print("B")

class C(A, B):
    def __init__(self):
        super(C, self).__init__()
        print("C")

if __name__ == '__main__':
    c = C()

我认为从 C init 中查找超级调用的顺序如下：A-B-Base-Base 还是我错了？

感谢您的回答。

Answer 1

使用下面的代码：

class A(Base):
    def __init__(self):
        super(A, self).__init__() #Remove this 1
        print("A")

希望对你有所帮助

Error: TypeError: __init__() takes 1 positional argument but 2 were given

Error: TypeError: __init__() takes 1 positional argument but 2 were given

python

init

super

Error: TypeError: init() takes 1 positional argument but 2 were given

Error: TypeError: init() takes 1 positional argument but 2 were given