将子视图定位在圆形视图的边缘

Position a subview on the edge of a circular shaped view

我正在尝试创建一个类似于下面模型的个人资料图片视图。它有一个小绿点来表示用户的在线状态。

我正在以编程方式创建视图,以便我可以重用它。以下是我目前的代码。

import UIKit

@IBDesignable
class ProfileView: UIView {

    fileprivate var imageView: UIImageView!
    fileprivate var onlineStatusView: UIView!
    fileprivate var onlineStatusDotView: UIView!


    @IBInspectable
    var image: UIImage? {
        get { return imageView.image }
        set { imageView.image = newValue }
    }

    @IBInspectable
    var shouldShowStatusDot: Bool = true


    override init(frame: CGRect) {
        super.init(frame: frame)
        initialize()
    }

    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        initialize()
    }

    private func initialize() {
        backgroundColor = .clear

        imageView = UIImageView(frame: bounds)
        imageView.backgroundColor = .lightGray
        imageView.clipsToBounds = true
        imageView.layer.cornerRadius = imageView.frame.height / 2
        addSubview(imageView)

        onlineStatusView = UIView(frame: CGRect(x: 0, y: 0, width: (bounds.height / 5), height: (bounds.height / 5)))
        onlineStatusView.backgroundColor = .white
        onlineStatusView.clipsToBounds = true
        onlineStatusView.layer.cornerRadius = onlineStatusView.frame.height / 2
        addSubview(onlineStatusView)

        onlineStatusDotView = UIView(frame: CGRect(x: 0, y: 0, width: (onlineStatusView.bounds.height / 1.3), height: (onlineStatusView.bounds.height / 1.3)))
        onlineStatusDotView.center = onlineStatusView.center
        onlineStatusDotView.backgroundColor = UIColor(red: 0.17, green: 0.71, blue: 0.45, alpha: 1.0)
        onlineStatusDotView.clipsToBounds = true
        onlineStatusDotView.layer.cornerRadius = onlineStatusDotView.frame.height / 2
        onlineStatusView.addSubview(onlineStatusDotView)
    }
}

我丢失的是如何将绿点视图固定在图像视图右上角的 圆形 边缘。显然视图的框架不是圆形的,所以我不知道在这种情况下使用什么自动布局约束。而且我也不想对值进行硬编码,因为它必须根据图像视图的大小移动。

我必须设置哪些自动布局约束才能使其到达正确的位置?

我在这里也上传了一个demo project

使用以下内容更改您的初始化函数: 您可以在给定的图像中看到结果 link...

  private func initialize() {
    backgroundColor = .clear

    imageView = UIImageView(frame: bounds)
    imageView.backgroundColor = .lightGray
    imageView.clipsToBounds = true
    imageView.layer.cornerRadius = imageView.frame.height / 2
    addSubview(imageView)

    onlineStatusView = UIView(frame: CGRect(x: 0, y: 0, width: (bounds.height / 5), height: (bounds.height / 5)))
    onlineStatusView.center = CGPoint(x: bounds.width / 7, y: bounds.height / 7)
    onlineStatusView.backgroundColor = .white
    onlineStatusView.clipsToBounds = true
    onlineStatusView.layer.cornerRadius = onlineStatusView.frame.height / 2
    addSubview(onlineStatusView)

    onlineStatusDotView = UIView(frame: CGRect(x: 0, y: 0, width: (onlineStatusView.bounds.height / 1.3), height: (onlineStatusView.bounds.height / 1.3)))
      onlineStatusDotView.center = CGPoint(x: onlineStatusView.frame.width / 2, y: onlineStatusView.frame.height / 2)
    onlineStatusDotView.backgroundColor = UIColor(red: 0.17, green: 0.71, blue: 0.45, alpha: 1.0)
    onlineStatusDotView.clipsToBounds = true
    onlineStatusDotView.layer.cornerRadius = onlineStatusDotView.frame.height / 2
    onlineStatusView.addSubview(onlineStatusDotView)
}

要将小绿圈放在大圈的右上角:

  1. 让小圆圈成为大圆圈的子视图。
  2. 添加约束,小圆的.centerX等于大圆的.trailingmultiplier等于0.8536
  3. 添加约束,小圆的 .centerY 等于大圆的 .bottommultiplier0.1464

注意: 两个 multiplier 是使用 三角学 通过查看单位圆并计算比率计算得出的: (distance from top of square containing unit circle)/(height of unit circle)(distance from left edge of square containing unit circle)/(width of unit circle)。在下面的示例代码中,我提供了一个名为 computeMultipliers(angle:)func,它计算任何 angle 的乘数(以度为单位)。避免完全 90180 的角度,因为这会产生 0 的倍数,而 A​​uto Layout 不喜欢。


这是独立的例子:

class ViewController: UIViewController {

    var bigCircle: UIView!
    var littleCircle: UIView!
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        bigCircle = UIView()
        bigCircle.translatesAutoresizingMaskIntoConstraints = false
        bigCircle.backgroundColor = .red
        view.addSubview(bigCircle)
        
        bigCircle.widthAnchor.constraint(equalToConstant: 240).isActive = true
        bigCircle.heightAnchor.constraint(equalToConstant: 240).isActive = true
        
        littleCircle = UIView()
        littleCircle.translatesAutoresizingMaskIntoConstraints = false
        littleCircle.backgroundColor = .green
        bigCircle.addSubview(littleCircle)

        bigCircle.centerXAnchor.constraint(equalTo: view.centerXAnchor).isActive = true
        bigCircle.centerYAnchor.constraint(equalTo: view.centerYAnchor).isActive = true
        
        littleCircle.widthAnchor.constraint(equalToConstant: 60).isActive = true
        littleCircle.heightAnchor.constraint(equalToConstant: 60).isActive = true
        
        let (hMult, vMult) = computeMultipliers(angle: 45)
        
        // position the little green circle using a multiplier on the right and bottom
        NSLayoutConstraint(item: littleCircle!, attribute: .centerX, relatedBy: .equal, toItem: bigCircle!, attribute: .trailing, multiplier: hMult, constant: 0).isActive = true
        NSLayoutConstraint(item: littleCircle!, attribute: .centerY, relatedBy: .equal, toItem: bigCircle!, attribute: .bottom, multiplier: vMult, constant: 0).isActive = true

    }

    override func viewDidLayoutSubviews() {
        super.viewDidLayoutSubviews()
        
        bigCircle.layer.cornerRadius = 0.5 * bigCircle.frame.height
        
        littleCircle.layoutIfNeeded()
        littleCircle.layer.cornerRadius = 0.5 * littleCircle.frame.height
    }

    func computeMultipliers(angle: CGFloat) -> (CGFloat, CGFloat) {
        let radians = angle * .pi / 180
        
        let h = (1.0 + cos(radians)) / 2
        let v = (1.0 - sin(radians)) / 2
        
        return (h, v)
    }
}


这是您的代码的修改版本。我添加了约束来设置小圆圈的大小,并将设置 cornerRadius 的代码移动到 layoutSubviews():

class ProfilePictureView: UIView {
    var bigCircle: UIView!
    var borderCircle: UIView!
    var littleCircle: UIView!
    
    override init(frame: CGRect) {
        super.init(frame: frame)
        initialize()
    }
    
    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        initialize()
    }
    
    private func initialize() {
        bigCircle = UIView(frame: bounds)
        bigCircle.backgroundColor = .red
        addSubview(bigCircle)
        
        borderCircle = UIView()
        borderCircle.translatesAutoresizingMaskIntoConstraints = false
        borderCircle.backgroundColor = .white
        bigCircle.addSubview(borderCircle)
        
        borderCircle.widthAnchor.constraint(equalTo: bigCircle.widthAnchor, multiplier: 1/3).isActive = true
        borderCircle.heightAnchor.constraint(equalTo: bigCircle.heightAnchor, multiplier: 1/3).isActive = true
        
        littleCircle = UIView()
        littleCircle.translatesAutoresizingMaskIntoConstraints = false
        littleCircle.backgroundColor = .green
        borderCircle.addSubview(littleCircle)
        
        littleCircle.widthAnchor.constraint(equalTo: borderCircle.widthAnchor, multiplier: 1/1.3).isActive = true
        littleCircle.heightAnchor.constraint(equalTo: borderCircle.heightAnchor, multiplier: 1/1.3).isActive = true
        littleCircle.centerXAnchor.constraint(equalTo: borderCircle.centerXAnchor).isActive = true
        littleCircle.centerYAnchor.constraint(equalTo: borderCircle.centerYAnchor).isActive = true
        
        let (hMult, vMult) = computeMultipliers(angle: 45)
        
        // position the border circle using a multiplier on the right and bottom
        NSLayoutConstraint(item: borderCircle!, attribute: .centerX, relatedBy: .equal, toItem: bigCircle!, attribute: .trailing, multiplier: hMult, constant: 0).isActive = true
        NSLayoutConstraint(item: borderCircle!, attribute: .centerY, relatedBy: .equal, toItem: bigCircle!, attribute: .bottom, multiplier: vMult, constant: 0).isActive = true
    }
    
    override func layoutSubviews() {
        super.layoutSubviews()
        bigCircle.layer.cornerRadius = bigCircle.frame.height / 2
        borderCircle.layoutIfNeeded()
        borderCircle.layer.cornerRadius = borderCircle.frame.height / 2
        littleCircle.layoutIfNeeded()
        littleCircle.layer.cornerRadius = littleCircle.frame.height / 2
    }
    
    private func computeMultipliers(angle: CGFloat) -> (CGFloat, CGFloat) {
        let radians = angle * .pi / 180
        
        let h = (1.0 + cos(radians)) / 2
        let v = (1.0 - sin(radians)) / 2
        
        return (h, v)
    }
}


computeMultipliers(angle:)

背后的数学解释

computeMultipliers(angle:) 的想法是应该为 水平约束 计算一个乘数,为 垂直约束 计算一个乘数].这些值是一个比例,范围从 01,其中 0 是垂直约束圆的 top0 是水平约束的圆的 left 边缘。同样,1 是垂直约束的圆的 底部 1 是圆的 边缘对于水平约束。

乘数是通过查看三角学中的 the unit circle 计算得出的。单位圆是坐标系上以(0, 0)为中心,半径1的圆。单位圆(根据定义)的好处是,圆上的一条线(从原点开始)与圆相交的点是 (cos(angle), sin(angle)),其中角度从正 x-axis 开始测量counter-clockwise 到与圆相交的线。注意单位圆的宽和高都是2.

sin(angle)cos(angle)-11

等式:

1 + cos(angle)

会根据角度从 02 不等。由于我们正在寻找从 01 的值,我们将其除以 2:

// compute the horizontal multiplier based upon the angle
let h = (1.0 + cos(radians)) / 2

在垂直方向,我们首先注意到坐标系是从数学意义上翻转的。在iOS中,y是向下生长的,而在数学中,y是向上生长的。考虑到这一点,垂直计算使用负 - 而不是 +:

1 - sin(angle)

同样,由于 sin-11,这个计算将从 02,所以我们除以 2:

// compute the vertical multiplier based upon the angle
let h = (1.0 - sin(radians)) / 2

这给了我们想要的结果。当角度为 90 度(或 .pi/2 弧度)时,sin1,因此垂直倍数将为 0。当角度为 270 度(或 3*.pi/2 弧度)时,sin-1,垂直倍数将为 1.

为什么要使用弧度? 一旦您理解了弧度是什么,它就会很直观。它们只是沿单位圆圆周的弧长。圆的周长公式是circumference = 2 * .pi * radius,所以单位圆的周长是2 * .pi。所以 360 度是 2 * .pi 弧度。