"TypeError: list indices must be integers or slices, not NoneType" in tictactoe game (Python 3)
"TypeError: list indices must be integers or slices, not NoneType" in tictactoe game (Python 3)
我一直在开发 Python 3 中的基本井字棋游戏,其中玩家与 AI 竞争以获胜。第一回合,代码成功执行,没有错误,但之后我得到了前面描述的错误。
我试过将 "board[move] = computer" 更改为 "move = computer",但这只是跳过了计算机的回合,因为没有填写任何内容。
我期望井字板的输出带有一个新的正方形,其中填充了 "O"。但我收到错误消息“board[move] = computer
类型错误:列表索引必须是整数或切片,而不是 NoneType"
代码如下:
X = "X"
O = "O"
EMPTY = " "
TIE = "TIE"
NUM_SQUARES = 9
def pieces():
go_first = ask_yes_no("Do you require the first move? (y/n): ")
if go_first == "y":
print("\nThen take the first move. You will need it.")
human = X
computer = O
else:
print("\nYour bravery will be your undoing... I'll go first")
computer = X
human = O
return computer, human
def new_board():
board = []
for square in range(NUM_SQUARES):
board.append(EMPTY)
return board
def legal_moves(board):
moves = []
for square in range(NUM_SQUARES):
if board[square] == EMPTY:
moves.append(square)
return moves
def winner(board):
WAYS_TO_WIN = ((0, 1, 2),
(3, 4, 5),
(6, 7, 8),
(0, 3, 6),
(1, 4, 7),
(2, 5, 8),
(0, 4, 8),
(2, 4, 6))
for row in WAYS_TO_WIN:
if board[row[0]] == board[row[1]] == board[row[2]] != EMPTY:
winner = board[row[0]]
return winner
if EMPTY not in board:
return TIE
return None
def human_move(board, human):
legal = legal_moves(board)
move = None
while move not in legal:
move = ask_number("Where will you move? (0 - 8):", 0,
NUM_SQUARES)
if move not in legal:
print("\nThat square is already occupied. Choose another.\n")
print("Fine...")
return move
def computer_move(board, computer, human):
board = board[:]
BEST_MOVES = (4, 0, 2, 6, 8, 1, 3, 5, 7)
print("I shall take square number", end=" ")
for move in legal_moves(board):
board[move] = computer
if winner(board) == computer:
print(move)
return move
board[move] = EMPTY
for move in legal_moves(board):
board[move] = human
if winner(board) == human:
print(move)
return move
board[move] = EMPTY
for move in BEST_MOVES:
if move in legal_moves(board):
print(move)
return move
def next_turn(turn):
if turn == X:
return O
else:
return X
def main():
computer, human = pieces()
turn = X
board = new_board()
display_board(board)
while not winner(board):
if turn == human:
move = human_move(board, human)
board[move] = human
else:
move = computer_move(board, computer, human)
board[move] = computer
display_board(board)
turn = next_turn(turn)
the_winner = winner(board)
main()
您的 legal_moves 功能已损坏,因为无论如何它 returns 就在第一个 'sqare' 之后。如果它已经被占用,它 returns 一个空列表。
只需将return
一个意图向下移动:
def legal_moves(board):
moves = []
for square in range(NUM_SQUARES):
if board[square] == EMPTY:
moves.append(square)
return moves
我一直在开发 Python 3 中的基本井字棋游戏,其中玩家与 AI 竞争以获胜。第一回合,代码成功执行,没有错误,但之后我得到了前面描述的错误。
我试过将 "board[move] = computer" 更改为 "move = computer",但这只是跳过了计算机的回合,因为没有填写任何内容。
我期望井字板的输出带有一个新的正方形,其中填充了 "O"。但我收到错误消息“board[move] = computer 类型错误:列表索引必须是整数或切片,而不是 NoneType"
代码如下:
X = "X"
O = "O"
EMPTY = " "
TIE = "TIE"
NUM_SQUARES = 9
def pieces():
go_first = ask_yes_no("Do you require the first move? (y/n): ")
if go_first == "y":
print("\nThen take the first move. You will need it.")
human = X
computer = O
else:
print("\nYour bravery will be your undoing... I'll go first")
computer = X
human = O
return computer, human
def new_board():
board = []
for square in range(NUM_SQUARES):
board.append(EMPTY)
return board
def legal_moves(board):
moves = []
for square in range(NUM_SQUARES):
if board[square] == EMPTY:
moves.append(square)
return moves
def winner(board):
WAYS_TO_WIN = ((0, 1, 2),
(3, 4, 5),
(6, 7, 8),
(0, 3, 6),
(1, 4, 7),
(2, 5, 8),
(0, 4, 8),
(2, 4, 6))
for row in WAYS_TO_WIN:
if board[row[0]] == board[row[1]] == board[row[2]] != EMPTY:
winner = board[row[0]]
return winner
if EMPTY not in board:
return TIE
return None
def human_move(board, human):
legal = legal_moves(board)
move = None
while move not in legal:
move = ask_number("Where will you move? (0 - 8):", 0,
NUM_SQUARES)
if move not in legal:
print("\nThat square is already occupied. Choose another.\n")
print("Fine...")
return move
def computer_move(board, computer, human):
board = board[:]
BEST_MOVES = (4, 0, 2, 6, 8, 1, 3, 5, 7)
print("I shall take square number", end=" ")
for move in legal_moves(board):
board[move] = computer
if winner(board) == computer:
print(move)
return move
board[move] = EMPTY
for move in legal_moves(board):
board[move] = human
if winner(board) == human:
print(move)
return move
board[move] = EMPTY
for move in BEST_MOVES:
if move in legal_moves(board):
print(move)
return move
def next_turn(turn):
if turn == X:
return O
else:
return X
def main():
computer, human = pieces()
turn = X
board = new_board()
display_board(board)
while not winner(board):
if turn == human:
move = human_move(board, human)
board[move] = human
else:
move = computer_move(board, computer, human)
board[move] = computer
display_board(board)
turn = next_turn(turn)
the_winner = winner(board)
main()
您的 legal_moves 功能已损坏,因为无论如何它 returns 就在第一个 'sqare' 之后。如果它已经被占用,它 returns 一个空列表。
只需将return
一个意图向下移动:
def legal_moves(board):
moves = []
for square in range(NUM_SQUARES):
if board[square] == EMPTY:
moves.append(square)
return moves