如何解析 json 数据 Android

Question

如何将具有相同标题的系列解析为一个数组列表

所以我得到了第 1 季和第 2 季的标题名称

最好的方法是什么

我的Json数据

{<br> "series":[<br> {<br> "title":"Jumping cat", "genre":"comedy", "year":2018, "season":1, "imdb":7, "info":"comdey series", "episodes":10, "cover":"poster" }, {<br> "title":"Jumping cat", "genre":"comedy", "year":2019, "season":2, "imdb":7, "info":"comdey series", "episodes":11, "cover":"poster" } ] }

Answer 1

以下代码将创建一个带有字符串键和 ArrayList 值的“HashMap”。 ArrayList 包含每个系列的模型：

try{
    JSONObject reader = new JSONObject(str);
    JSONArray array = reader.optJSONArray("series");
    HashMap<String, ArrayList<YourModel>> map =  new HashMap<>();
    for(int i=0;i<array.length();i++){
        JSONObject innerObject = array.getJSONObject(i);
        if(map.get(innerObject.getString("title")) != null){ // check if the title already exists, then add it to it's list
            ArrayList<YourModel> arrayList = map.get(innerObject.getString("title"));
            arrayList.add(new YourModel(innerObject));
        }else{ // if the title does not exist, create new ArrayList
            ArrayList<YourModel> arrayList = new ArrayList<>();
            arrayList.add(new YourModel(innerObject));
            map.put(innerObject.getString("title"),arrayList);
        }
    }
}catch (JSONException e){
    // Do error handling
}

Answer 2

要获取 Json 的信息，您总是需要两件事

POJO 的模型 class ob 您将获得的对象
选择使用一个或JsonJava原生的解析器或第三方的Gson

希望对您有所帮助:D

Answer 3

您的回复以列表开头

@SerializedName("series")
@Expose
private List<Series> series = null;

List model class

@SerializedName("title")
@Expose
private String title;
@SerializedName("genre")
@Expose
private String genre;
@SerializedName("year")
@Expose
private Integer year;
@SerializedName("season")
@Expose
private Integer season;
@SerializedName("imdb")
@Expose
private Integer imdb;
@SerializedName("info")
@Expose
private String info;
@SerializedName("episodes")
@Expose
private Integer episodes;
@SerializedName("cover")
@Expose
private String cover;

And create getter setter method

Answer 4

如果您不想再添加第 3 方。您可以在几行中完成此操作。是的，它是体力劳动，但它会节省大量添加到您的 APK 的字节码。

    public class Serie {
        public String title;
        public String genere;
        public int year;
        public int season;
        public int imdb;
        public String info;
        public int episodes;
        public String cover;

        public static Serie toObject(JSONObject o) throws JSONException {
            Serie s = new Serie();
            s.title = o.getString("title");
            s.genere = o.getString("genre");
            s.year = o.getInt("year");
            s.season = o.getInt("season");
            s.imdb = o.getInt("imdb");
            s.info = o.getString("info");
            s.episodes = o.getInt("episodes");
            s.cover = o.getString("cover");
            return s;
        }

         public static List<Serie> toArray(String json) throws JSONException {
            JSONObject oo = new JSONObject(json);
            JSONArray a = oo.getJSONArray("series");
            List<Serie> l = new ArrayList<>(a.length());
            for (int i =0; i<a.length(); i++ ) {
                JSONObject o = a.getJSONObject(i);
                l.add(Serie.toObject(o));
            }
            return l;
        }
    }

    // usage 
    try {
       List<Serie> ll = Serie.toArray(s);
       System.out.println(ll.toString());
    } catch (JSONException e) {
       e.printStackTrace();
    }

Answer 5

您可以使用 Google 的 gson library for simply parse json into java classe and vice versa. An example for how to use gson found here

如何解析 json 数据 Android

How to parse json Data Android

android

json

android-volley