'CustomEnum.Case' 可分配给类型 'T' 的约束,但 'T' 可以用约束的不同子类型 'CustomEnum' 实例化
'CustomEnum.Case' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'CustomEnum'
我正在定义一个接口,其中 属性 的类型之一取决于绑定到枚举的通用参数 P。我正在使用以下方法:
export enum Scopes {
Fruit = 'fruit',
Vegetables = 'vegetables',
}
export enum FruitItemTypes {
Strawberry = 'strawberry',
Rasberry = 'rasberry'
}
export enum VegetableItemTypes {
Potatoes = 'potatoes',
Carrots = 'currency',
}
export type ItemTypes = FruitItemTypes | VegetableItemTypes
interface ItemTypeForScope {
[Scopes.Fruit]: FruitItemTypes;
[Scopes.Vegetables]: VegetableItemTypes;
}
export interface Item {
id: string;
type: ItemTypes;
}
export interface ScopedItem<T extends Scopes> extends Item {
type: ItemTypeForScope[T];
}
export interface ScopedData<T extends Scopes> {
items: ScopedItem<T>[];
}
export type Data = { [scope in Scopes]: ScopedData<scope> };
我还想使用 ScopedItem<T>
作为以下函数的 return 类型:
const getItemType = <T extends Scopes>(data: Data, scope: T): ScopedItem<T>[] => {
return data[scope].items
}
但是我收到以下错误,但根据我的说法,通用参数 T 最终将成为枚举案例之一。
Type 'ScopedItem<Scopes.Fruit>[] | ScopedItem<Scopes.Vegetables>[]' is not assignable to type 'ScopedItem<T>[]'.
Type 'ScopedItem<Scopes.Fruit>[]' is not assignable to type 'ScopedItem<T>[]'.
Type 'ScopedItem<Scopes.Fruit>' is not assignable to type 'ScopedItem<T>'.
Type 'Scopes.Fruit' is not assignable to type 'T'.
'Scopes.Fruit' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'Scopes'.
我相信这里的问题与 this issue... you want the compiler to evaluate {[K in Scopes]: ScopedData<K>}[P]
to something like ScopedData[P]
, where P
is a generic type parameter that extends K
. But the compiler doesn't do this sort of higher-order reasoning where a generic function of a concrete type is simiplified before the generic type is resolved; there has been a suggestion 中描述的问题相同,在某些情况下会发生这种情况,但从 TS3.5 开始就不存在了。
因此,变通办法... 编译器可以验证以下内容:
const getItemType = <T extends Scopes>(
data: Data,
scope: T
): Data[T]["items"] => {
return data[scope].items;
};
而不是 return 将 data[scope].items
的类型设置为 ScopedItem<T>[]
,return 将其设置为 Data[T]["items"]
。那些将变成同一件事,当您实际 调用 getItemType()
一个具体类型的 scope
参数时,它最终将成为相同的具体类型。
或者你可以承认自己的推理能力比编译器高明,然后用一个type assertion让编译器知道谁是老大:
const getItemTypeAssertion = <T extends Scopes>(
data: Data,
scope: T
): ScopedItem<T>[] => {
return (data[scope] as ScopedData<T>).items; // I am smarter than the compiler
};
希望其中之一对您有用。祝你好运!
我正在定义一个接口,其中 属性 的类型之一取决于绑定到枚举的通用参数 P。我正在使用以下方法:
export enum Scopes {
Fruit = 'fruit',
Vegetables = 'vegetables',
}
export enum FruitItemTypes {
Strawberry = 'strawberry',
Rasberry = 'rasberry'
}
export enum VegetableItemTypes {
Potatoes = 'potatoes',
Carrots = 'currency',
}
export type ItemTypes = FruitItemTypes | VegetableItemTypes
interface ItemTypeForScope {
[Scopes.Fruit]: FruitItemTypes;
[Scopes.Vegetables]: VegetableItemTypes;
}
export interface Item {
id: string;
type: ItemTypes;
}
export interface ScopedItem<T extends Scopes> extends Item {
type: ItemTypeForScope[T];
}
export interface ScopedData<T extends Scopes> {
items: ScopedItem<T>[];
}
export type Data = { [scope in Scopes]: ScopedData<scope> };
我还想使用 ScopedItem<T>
作为以下函数的 return 类型:
const getItemType = <T extends Scopes>(data: Data, scope: T): ScopedItem<T>[] => {
return data[scope].items
}
但是我收到以下错误,但根据我的说法,通用参数 T 最终将成为枚举案例之一。
Type 'ScopedItem<Scopes.Fruit>[] | ScopedItem<Scopes.Vegetables>[]' is not assignable to type 'ScopedItem<T>[]'.
Type 'ScopedItem<Scopes.Fruit>[]' is not assignable to type 'ScopedItem<T>[]'.
Type 'ScopedItem<Scopes.Fruit>' is not assignable to type 'ScopedItem<T>'.
Type 'Scopes.Fruit' is not assignable to type 'T'.
'Scopes.Fruit' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'Scopes'.
我相信这里的问题与 this issue... you want the compiler to evaluate {[K in Scopes]: ScopedData<K>}[P]
to something like ScopedData[P]
, where P
is a generic type parameter that extends K
. But the compiler doesn't do this sort of higher-order reasoning where a generic function of a concrete type is simiplified before the generic type is resolved; there has been a suggestion 中描述的问题相同,在某些情况下会发生这种情况,但从 TS3.5 开始就不存在了。
因此,变通办法... 编译器可以验证以下内容:
const getItemType = <T extends Scopes>(
data: Data,
scope: T
): Data[T]["items"] => {
return data[scope].items;
};
而不是 return 将 data[scope].items
的类型设置为 ScopedItem<T>[]
,return 将其设置为 Data[T]["items"]
。那些将变成同一件事,当您实际 调用 getItemType()
一个具体类型的 scope
参数时,它最终将成为相同的具体类型。
或者你可以承认自己的推理能力比编译器高明,然后用一个type assertion让编译器知道谁是老大:
const getItemTypeAssertion = <T extends Scopes>(
data: Data,
scope: T
): ScopedItem<T>[] => {
return (data[scope] as ScopedData<T>).items; // I am smarter than the compiler
};
希望其中之一对您有用。祝你好运!