API 平台在 normalizationContext 和 denormalizationContext 时未显示名字和姓氏
API Platform Did not show First Name And Last Name Upon normalizationContext and denormalizationContext
我是 API 平台的新手,我在 API 平台上的用户实体的 normalizationContext 和 denormalizationContext 有一些问题。当我将 normalizationContext 和 denormalizationContext 添加到 ApiResources 时,是的,我确实在 first_name 和 last_name 变量上方添加了 @Groups({"user:read", "user:write"})
。但是当尝试从 api 平台获取 post 数据时,我没有看到我的 first_name 和 last_name 变量选项。
这是我的用户实体
<?php
namespace App\Entity;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;
use ApiPlatform\Core\Annotation\ApiResource;
use Symfony\Component\Serializer\Annotation\Groups;
use Symfony\Component\Validator\Constraints as Assert;
/**
* @ORM\Entity(repositoryClass="App\Repository\UserRepository")
* @ApiResource(
* normalizationContext={"groups"={"user:read"}},
* denormalizationContext={"groups"={"user:write"}},
* )
*/
class User implements UserInterface
{
/**
* @ORM\Id()
* @ORM\GeneratedValue()
* @ORM\Column(type="integer")
*/
private $id;
/**
* @ORM\Column(type="string", length=180, unique=true)
* @Groups({"user:read", "user:write"})
* @Assert\NotBlank()
* @Assert\Email()
*/
private $email;
/**
* @ORM\Column(type="json")
*/
private $roles = [];
/**
* @var string The hashed password
* @ORM\Column(type="string")
* @Groups({"user:write"})
*/
private $password;
/**
* @ORM\Column(type="string", length=255)
* @Groups({"user:read", "user:write"})
*/
private $first_name;
/**
* @ORM\Column(type="string", length=255)
* @Groups({"user:read", "user:write"})
*/
private $last_name;
/**
* @ORM\Column(type="date")
* @Groups({"user:read", "user:write"})
*/
private $dob;
public function getId(): ?int
{
return $this->id;
}
public function getEmail(): ?string
{
return $this->email;
}
public function setEmail(string $email): self
{
$this->email = $email;
return $this;
}
/**
* A visual identifier that represents this user.
*
* @see UserInterface
*/
public function getUsername(): string
{
return (string) $this->email;
}
/**
* @see UserInterface
*/
public function getRoles(): array
{
$roles = $this->roles;
// guarantee every user at least has ROLE_USER
$roles[] = 'ROLE_USER';
return array_unique($roles);
}
public function setRoles(array $roles): self
{
$this->roles = $roles;
return $this;
}
/**
* @see UserInterface
*/
public function getPassword(): string
{
return (string) $this->password;
}
public function setPassword(string $password): self
{
$this->password = $password;
return $this;
}
/**
* @see UserInterface
*/
public function getSalt()
{
// not needed when using the "bcrypt" algorithm in security.yaml
}
/**
* @see UserInterface
*/
public function eraseCredentials()
{
// If you store any temporary, sensitive data on the user, clear it here
// $this->plainPassword = null;
}
public function getFirstName(): ?string
{
return $this->first_name;
}
public function setFirstName(string $first_name): self
{
$this->first_name = $first_name;
return $this;
}
public function getLastName(): ?string
{
return $this->last_name;
}
public function setLastName(string $last_name): self
{
$this->last_name = $last_name;
return $this;
}
public function getDob(): ?\DateTimeInterface
{
return $this->dob;
}
public function setDob(\DateTimeInterface $dob): self
{
$this->dob = $dob;
return $this;
}
}
我想为读写组的 API 平台提供 first_name 和 last_name 变量。我该如何解决这个问题?
您需要对属性使用驼峰式命名法。默认情况下,Doctrine 期望驼峰命名法。 Doctrine 没有将 getFirstName() 识别为 $first_name 的 getter。并且由于 属性 被声明为私有 api-平台无法获取该值。
这应该有效:
/**
* @ORM\Column(type="string", length=255)
* @Groups({"user:read", "user:write"})
*/
private $firstName;
public function getFirstName(): ?string
{
return $this->firstName;
}
或者您可以尝试强制教义使用下划线,如下所示:
doctrine:
orm:
naming_strategy: doctrine.orm.naming_strategy.underscore
我是 API 平台的新手,我在 API 平台上的用户实体的 normalizationContext 和 denormalizationContext 有一些问题。当我将 normalizationContext 和 denormalizationContext 添加到 ApiResources 时,是的,我确实在 first_name 和 last_name 变量上方添加了 @Groups({"user:read", "user:write"})
。但是当尝试从 api 平台获取 post 数据时,我没有看到我的 first_name 和 last_name 变量选项。
这是我的用户实体
<?php
namespace App\Entity;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;
use ApiPlatform\Core\Annotation\ApiResource;
use Symfony\Component\Serializer\Annotation\Groups;
use Symfony\Component\Validator\Constraints as Assert;
/**
* @ORM\Entity(repositoryClass="App\Repository\UserRepository")
* @ApiResource(
* normalizationContext={"groups"={"user:read"}},
* denormalizationContext={"groups"={"user:write"}},
* )
*/
class User implements UserInterface
{
/**
* @ORM\Id()
* @ORM\GeneratedValue()
* @ORM\Column(type="integer")
*/
private $id;
/**
* @ORM\Column(type="string", length=180, unique=true)
* @Groups({"user:read", "user:write"})
* @Assert\NotBlank()
* @Assert\Email()
*/
private $email;
/**
* @ORM\Column(type="json")
*/
private $roles = [];
/**
* @var string The hashed password
* @ORM\Column(type="string")
* @Groups({"user:write"})
*/
private $password;
/**
* @ORM\Column(type="string", length=255)
* @Groups({"user:read", "user:write"})
*/
private $first_name;
/**
* @ORM\Column(type="string", length=255)
* @Groups({"user:read", "user:write"})
*/
private $last_name;
/**
* @ORM\Column(type="date")
* @Groups({"user:read", "user:write"})
*/
private $dob;
public function getId(): ?int
{
return $this->id;
}
public function getEmail(): ?string
{
return $this->email;
}
public function setEmail(string $email): self
{
$this->email = $email;
return $this;
}
/**
* A visual identifier that represents this user.
*
* @see UserInterface
*/
public function getUsername(): string
{
return (string) $this->email;
}
/**
* @see UserInterface
*/
public function getRoles(): array
{
$roles = $this->roles;
// guarantee every user at least has ROLE_USER
$roles[] = 'ROLE_USER';
return array_unique($roles);
}
public function setRoles(array $roles): self
{
$this->roles = $roles;
return $this;
}
/**
* @see UserInterface
*/
public function getPassword(): string
{
return (string) $this->password;
}
public function setPassword(string $password): self
{
$this->password = $password;
return $this;
}
/**
* @see UserInterface
*/
public function getSalt()
{
// not needed when using the "bcrypt" algorithm in security.yaml
}
/**
* @see UserInterface
*/
public function eraseCredentials()
{
// If you store any temporary, sensitive data on the user, clear it here
// $this->plainPassword = null;
}
public function getFirstName(): ?string
{
return $this->first_name;
}
public function setFirstName(string $first_name): self
{
$this->first_name = $first_name;
return $this;
}
public function getLastName(): ?string
{
return $this->last_name;
}
public function setLastName(string $last_name): self
{
$this->last_name = $last_name;
return $this;
}
public function getDob(): ?\DateTimeInterface
{
return $this->dob;
}
public function setDob(\DateTimeInterface $dob): self
{
$this->dob = $dob;
return $this;
}
}
我想为读写组的 API 平台提供 first_name 和 last_name 变量。我该如何解决这个问题?
您需要对属性使用驼峰式命名法。默认情况下,Doctrine 期望驼峰命名法。 Doctrine 没有将 getFirstName() 识别为 $first_name 的 getter。并且由于 属性 被声明为私有 api-平台无法获取该值。
这应该有效:
/**
* @ORM\Column(type="string", length=255)
* @Groups({"user:read", "user:write"})
*/
private $firstName;
public function getFirstName(): ?string
{
return $this->firstName;
}
或者您可以尝试强制教义使用下划线,如下所示:
doctrine:
orm:
naming_strategy: doctrine.orm.naming_strategy.underscore